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September 27, 2025, 03:03:35 am
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Author Topic: TyErd's questions  (Read 42488 times)  Share 

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kenhung123

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Re: TyErd's questions
« Reply #225 on: June 13, 2010, 01:36:59 pm »
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Is there at all many tricks to find the gradient graph only given the original graph? This is extremely tricky!
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TyErd

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Re: TyErd's questions
« Reply #226 on: June 13, 2010, 01:41:25 pm »
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Quote from: kenhung123 on June 13, 2010, 01:36:59 pm
Is there at all many tricks to find the gradient graph only given the original graph? This is extremely tricky!

I agree, it is very tricky at first, but I found practice was the key. I did all the ones in essentials atleast three times even the basic ones. I dont think theres any tricks with them but If there is I'd be eager to know.
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kenhung123

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Re: TyErd's questions
« Reply #227 on: June 13, 2010, 01:43:15 pm »
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Do you throw these types of questions at us in exams? Definately would take some time to figure out and then try to confirm its the right answer.
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brightsky

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Re: TyErd's questions
« Reply #228 on: June 13, 2010, 01:47:51 pm »
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Because the x-coordinate of P is 2 and P lies on , the y-coordinate of P is given by . So P .

Because the x-coordinate of Q is 2+h and Q lies on , the y-coordinate of Q is given by . So Q .

So the gradient of P,Q is given by .
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brightsky

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Re: TyErd's questions
« Reply #229 on: June 13, 2010, 01:54:30 pm »
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Quote from: kenhung123 on June 13, 2010, 01:36:59 pm
Is there at all many tricks to find the gradient graph only given the original graph? This is extremely tricky!
Just find the equation of the original graph and then derive it to get gradient graph as far as I know.
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the.watchman

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Re: TyErd's questions
« Reply #230 on: June 13, 2010, 02:01:57 pm »
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Quote from: brightsky on June 13, 2010, 01:54:30 pm
Quote from: kenhung123 on June 13, 2010, 01:36:59 pm
Is there at all many tricks to find the gradient graph only given the original graph? This is extremely tricky!
Just find the equation of the original graph and then derive it to get gradient graph as far as I know.

Well, you can and may be asked to sketch gradient graphs, given the graph of any function
To tackle these questions, look for stationary points and be sure to note the sign of the gradient between any of these.
Also, be careful with any endpoints and cusps that may appear, because functions are not differentiable at these.
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TyErd

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Re: TyErd's questions
« Reply #231 on: June 13, 2010, 05:06:08 pm »
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use the chain rule to prove , where n is a negative number. I dont get it.
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TyErd

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Re: TyErd's questions
« Reply #232 on: June 13, 2010, 05:28:36 pm »
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Um.. if

I can get through about three quarters of it but then I get stuck. I dont like simplifying, its a pain.
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kenhung123

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Re: TyErd's questions
« Reply #233 on: June 13, 2010, 05:32:39 pm »
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Quote from: TyErd on June 13, 2010, 05:06:08 pm
use the chain rule to prove , where n is a negative number. I dont get it.
Hmm not sure about the "where n is a negative number" but I would just do it normally like lol thats basically it I guess...
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kenhung123

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Re: TyErd's questions
« Reply #234 on: June 13, 2010, 05:38:04 pm »
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Quote from: TyErd on June 13, 2010, 05:28:36 pm
Um.. if

I can get through about three quarters of it but then I get stuck. I dont like simplifying, its a pain.
Use chain rule to get

=>
You can see that the first bracket is equal to 2*y from original equation so you can substitute that in and get the ans
« Last Edit: June 13, 2010, 05:48:13 pm by kenhung123 »
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TyErd

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Re: TyErd's questions
« Reply #235 on: June 13, 2010, 05:45:01 pm »
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how'd u get the first half of your first line?
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kenhung123

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Re: TyErd's questions
« Reply #236 on: June 13, 2010, 05:48:25 pm »
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Sorry missed a bracket
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TyErd

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Re: TyErd's questions
« Reply #237 on: June 13, 2010, 06:00:39 pm »
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  or is it suppose to be in that first part?
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kenhung123

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Re: TyErd's questions
« Reply #238 on: June 13, 2010, 06:15:20 pm »
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1
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TyErd

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Re: TyErd's questions
« Reply #239 on: June 13, 2010, 06:30:32 pm »
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Quote
Use chain rule to get

=>
You can see that the first bracket is equal to 2*y from original equation so you can substitute that in and get the ans

So the first line should look like this?  
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