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September 25, 2025, 09:45:50 pm
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Author Topic: TyErd's questions  (Read 42425 times)  Share 

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TyErd

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Re: TyErd's questions
« Reply #90 on: April 26, 2010, 01:28:02 am »
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oh crap i just realised my mistake. Your right mandy!
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TyErd

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Re: TyErd's questions
« Reply #91 on: April 26, 2010, 03:06:43 am »
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The rule for the inverse relation of the function with rule  is ?

and also whats the difference between the inverse function and inverse relation?
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moekamo

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Re: TyErd's questions
« Reply #92 on: April 26, 2010, 04:55:20 am »
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which is the inverse relation, since it contains both positive and negative square roots, if it were a function it could only have either positive or negative square roots

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TyErd

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Re: TyErd's questions
« Reply #93 on: April 26, 2010, 09:57:00 am »
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OH okay! thankyou for clearing that up.
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TyErd

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Re: TyErd's questions
« Reply #94 on: April 26, 2010, 10:01:53 am »
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so basically for an inverse relation, it doesn't have to be a one to one function?
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the.watchman

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Re: TyErd's questions
« Reply #95 on: April 26, 2010, 10:09:37 am »
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Quote from: TyErd on April 26, 2010, 10:01:53 am
so basically for an inverse relation, it doesn't have to be a one to one function?

A relation is basically an eqn linking two variables, it can be a function but it doesn't have to be.
So if you are asked to find the inverse relation, you use the same process, however, be aware that your answer may not be a function
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TyErd

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Re: TyErd's questions
« Reply #96 on: April 26, 2010, 10:54:42 am »
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ohhh so all functions are relations right?...and for this one if i was told to find the inverse function then first I would have to make it a one to one function by restricting the domain and then proceed to find the  inverse but if it asked for the inverse relation i dont have to restrict the domain.
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Blakhitman

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Re: TyErd's questions
« Reply #97 on: April 26, 2010, 10:57:31 am »
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And then the positive or negative square root depends on how you restricted the domain.
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TyErd

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Re: TyErd's questions
« Reply #98 on: April 26, 2010, 10:59:57 am »
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Yes, thankyou! makes so much more sense now :)
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the.watchman

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Re: TyErd's questions
« Reply #99 on: April 26, 2010, 11:00:26 am »
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Note, the choice of which root to take depends on the range restriction of the inverse (remembering that )
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TyErd

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Re: TyErd's questions
« Reply #100 on: April 26, 2010, 11:03:56 am »
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yup :)
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TyErd

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Re: TyErd's questions
« Reply #101 on: April 26, 2010, 11:32:52 am »
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if       Find:

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the.watchman

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Re: TyErd's questions
« Reply #102 on: April 26, 2010, 11:37:20 am »
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Well, using the complementary angle formulas,

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TyErd

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Re: TyErd's questions
« Reply #103 on: April 26, 2010, 11:52:03 am »
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can you use identities to solve this?
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the.watchman

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Re: TyErd's questions
« Reply #104 on: April 26, 2010, 11:57:03 am »
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Quote from: TyErd on April 26, 2010, 11:52:03 am
can you use identities to solve this?

Of course, you can use whatever formulas you like, as long as you can get the answer with the information they give you :)
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Remember, remember the 5th of November

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