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Author Topic: TyErd's questions  (Read 42772 times)  Share 

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TyErd

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Re: TyErd's questions
« Reply #435 on: July 04, 2010, 06:40:42 pm »
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Okay thankyou, um for the one the answers are
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m@tty

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Re: TyErd's questions
« Reply #436 on: July 04, 2010, 06:42:45 pm »
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Any terminals equally spaced about a zero will satisfy the equation.

So that answer is satisfactory.

Were there any restrictions with the question?
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TyErd

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Re: TyErd's questions
« Reply #437 on: July 04, 2010, 06:52:37 pm »
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what do you mean by any terminals equally spaced about a zero? and nah there weren't any restrictions
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TyErd

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Re: TyErd's questions
« Reply #438 on: July 04, 2010, 07:28:20 pm »
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also I need some help with this question:

 if   is equal to..?
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brightsky

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Re: TyErd's questions
« Reply #439 on: July 04, 2010, 07:38:19 pm »
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So in this case:



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TyErd

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Re: TyErd's questions
« Reply #440 on: July 04, 2010, 07:55:19 pm »
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thankyou!
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m@tty

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Re: TyErd's questions
« Reply #441 on: July 04, 2010, 08:11:00 pm »
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Quote from: TyErd on July 04, 2010, 06:52:37 pm
what do you mean by any terminals equally spaced about a zero? and nah there weren't any restrictions

Because a sine curve is symmetrical, the area confined from a zero, say x=0, to another value, say x=a, will be equal to the area from x=-a to x=0. But, since sine changes sign at a zero, one of the areas will be negative, meaning that the areas will sum to zero.

That was probably confusing, but consider one period of a sine curve; both 'halves' are of equal area, but one segment is above the x-axis while the other is below. So when you take the integral over the entire period you get zero.

due to symmetry. (You can replace 0 with any other x-intercept.)

Hopefully this is clearer =S
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TyErd

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Re: TyErd's questions
« Reply #442 on: July 04, 2010, 08:31:07 pm »
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Ohhh I getcha, its much easier to understand with a graph.    would also be a solution yeah?  
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Re: TyErd's questions
« Reply #443 on: July 04, 2010, 09:16:53 pm »
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Yep.
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TyErd

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Re: TyErd's questions
« Reply #444 on: July 04, 2010, 09:20:43 pm »
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ok thnkyou vm
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TyErd

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Re: TyErd's questions
« Reply #445 on: July 06, 2010, 12:13:55 am »
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A computer manufacturer notes that 5% of the computers are returned owing to faulty disk drives, 2% are returned owing to faulty keyboards and  0.3% are returned because both disk drives and keyboards are faulty.

Find the probability that the next computer has a faulty disk drive and a working keyboard.

I did: 0.05+0.98 - 0.03 = 1.

I dont get it
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vexx

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Re: TyErd's questions
« Reply #446 on: July 06, 2010, 12:26:39 am »
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^ TyErd, it's fairly simple in that using the formula
Pr(AuB) since it's it is both faulty disk(A) and working keyboard(B) which = Pr(A) + Pr(B) - Pr(AnB)
That's just the rule used, and so it's 0.05 (5%) + 0.02 (2%) - 0.003 (0.3%) = 0.067
Do you get it?
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TyErd

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Re: TyErd's questions
« Reply #447 on: July 06, 2010, 12:32:19 am »
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the answers actually 0.047.
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vexx

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Re: TyErd's questions
« Reply #448 on: July 06, 2010, 12:55:36 am »
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Quote from: TyErd on July 06, 2010, 12:32:19 am
the answers actually 0.047.

so sorry i thought you said both were faulty for some reason as i did this question as one of my randomly selected ones:)

well
faulty disk drive and a working keyboard.
as i calculated before, pr(either are faulty)=0.067
but we just want pr(faulty disk drive and working keyboard) = pr (either) - pr(faulty keyboard) as the keyboard is working so we cannot account for a faulty keyboard
=0.047 :p
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TyErd

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Re: TyErd's questions
« Reply #449 on: July 06, 2010, 01:12:59 am »
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okay i get it now, thankyou vm vexx
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