Login

Search the forums now!

Welcome, Guest. Please login or register.

February 24, 2026, 05:23:35 pm
Pages: [1]   Go Down

Author Topic: Deceleration implication  (Read 607 times)  Share 

0 Members and 1 Guest are viewing this topic.

kenhung123

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 3373
  • Respect: +7
Deceleration implication
« on: May 30, 2010, 09:24:34 pm »
0
When a vehicle or someone riding a bike decelerate, does it imply that the force of engine =0 So Fnet=Friction?
Logged

m@tty

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 4324
  • Respect: +33
  • School: Heatherton Christian College
  • School Grad Year: 2010
Re: Deceleration implication
« Reply #1 on: May 30, 2010, 09:30:30 pm »
0
No. All that it implies is that the net force has a component opposite to the motion.

You could be providing 800N driving force, but if there is more than that opposing the motion (ie. on a slope component of weight, and friction) then there would be deceleration. Confusing example, but the principle still applies.
« Last Edit: May 30, 2010, 09:33:16 pm by m@tty »
Logged
2009/2010: Mathematical Methods(non-CAS) ; Business Management | English ; Literature - Physics ; Chemistry - Specialist Mathematics ; MUEP Maths

96.85

2011-2015: Bachelor of Aerospace Engineering and Bachelor of Science, Monash University

2015-____: To infinity and beyond.

Blakhitman

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1954
  • Respect: +7
Re: Deceleration implication
« Reply #2 on: May 30, 2010, 09:31:51 pm »
0
Friction force > Driving force.

so the Net force is towards the opposite direction of the motion.
Logged
Pages: [1]   Go Up