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May 02, 2025, 06:55:29 pm

Author Topic: Question 13 and 14 on Motion  (Read 6942 times)  Share 

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qwertyda2nd

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Question 13 and 14 on Motion
« on: June 08, 2010, 09:40:03 pm »
Do you think that if i got 100N/m for Q13 that they would mark Q14 consequentially as I used that answer to find the change in energy (that i got =0)?

Stormer

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Re: Question 13 and 14 on Motion
« Reply #1 on: June 08, 2010, 09:40:43 pm »
It seems a lot of people have got 100N/m for Q13. I put 50N/m but i'm not sure that's correct now.
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Akirus

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Re: Question 13 and 14 on Motion
« Reply #2 on: June 08, 2010, 09:44:55 pm »
It seems a lot of people have got 100N/m for Q13. I put 50N/m but i'm not sure that's correct now.

Where does 100N/m come from..?

Stormer

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Re: Question 13 and 14 on Motion
« Reply #3 on: June 08, 2010, 09:46:33 pm »
Energy calculations apparently. Physics teacher at my school had 100N/m as well.
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Akirus

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Re: Question 13 and 14 on Motion
« Reply #4 on: June 08, 2010, 09:47:41 pm »
Energy calculations apparently. Physics teacher at my school had 100N/m as well.

Incorrect assumption, since the gravitational energy is not necessarily transformed completely into elastic potential energy. It's 50N/m.

Stormer

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Re: Question 13 and 14 on Motion
« Reply #5 on: June 08, 2010, 09:48:33 pm »
Fantastic.

They reasoned that it had something to do with the force not being constant. Wouldn't have a clue.
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googoo

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Re: Question 13 and 14 on Motion
« Reply #6 on: June 08, 2010, 09:49:20 pm »
which school?

Juddinator

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Re: Question 13 and 14 on Motion
« Reply #7 on: June 08, 2010, 09:49:48 pm »
I had 50N/m as well. Didn't think twice about it tbh....

Stormer

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Re: Question 13 and 14 on Motion
« Reply #8 on: June 08, 2010, 09:51:04 pm »
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Stroodle

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Re: Question 13 and 14 on Motion
« Reply #9 on: June 08, 2010, 09:55:31 pm »
I'm confident that it's 50 and 4. My physics teacher is seriously amazing, and this is what he got.

Akirus

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Re: Question 13 and 14 on Motion
« Reply #10 on: June 08, 2010, 09:57:33 pm »
I'm confident that it's 50 and 4. My physics teacher is seriously amazing, and this is what he got.

Kyzoo's teacher is the head examiner (at least, that's what he said) and he said it's 4J, whatever that is worth.

It doesn't matter how it's pulled down, because it's the weight force that is maintaining the extension the final position.

Blakhitman

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Re: Question 13 and 14 on Motion
« Reply #11 on: June 08, 2010, 10:09:54 pm »
I'm confident that it's 50 and 4. My physics teacher is seriously amazing, and this is what he got.

Kyzoo's teacher is the head examiner (at least, that's what he said) and he said it's 4J, whatever that is worth.

It doesn't matter how it's pulled down, because it's the weight force that is maintaining the extension the final position.

Head assessor probably, examiners aren't allowed to teach :P

kyzoo

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Re: Question 13 and 14 on Motion
« Reply #12 on: June 08, 2010, 10:20:16 pm »
>.< Assistant chief head assessor lol, and that doesn't mean he's right 0.o everyone makes mistakes (our physics class are full of examples of this haha)
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Akirus

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Re: Question 13 and 14 on Motion
« Reply #13 on: June 08, 2010, 10:21:40 pm »
I'm confident that it's 50 and 4. My physics teacher is seriously amazing, and this is what he got.

Kyzoo's teacher is the head examiner (at least, that's what he said) and he said it's 4J, whatever that is worth.

It doesn't matter how it's pulled down, because it's the weight force that is maintaining the extension the final position.

Head assessor probably, examiners aren't allowed to teach :P

Ah, right. I thought they were the same thing anyway.

I don't see how it's wrong though.

Ball Lightning

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Re: Question 13 and 14 on Motion
« Reply #14 on: June 08, 2010, 10:23:27 pm »
100 comes from this which i posted in another thread:

I equated the energy at the top unstretched with the energy .4m below, the spring energy.

This gave:

mgh=(1/2)*k*x^2

which came out to k=100

As there is no loss in energy (as the hand does not take away from either sides energy)

8=8 Therefore there is a 0 change in energy, and it is conserved.

From a brief discussion we had with our teacher he agreed with us about this answer.
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