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October 04, 2025, 11:43:55 am

Author Topic: Question 9 Part C  (Read 3047 times)  Share 

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joocoobpootooloo

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Question 9 Part C
« on: June 09, 2010, 08:57:58 pm »
Question 9C).....
if i forgot to mention hydrogen bonding in regards to propan-1-ol but mentioned its polarity and dipole dipole bonds and that butane is non polar and has dispersion forces i might get the 3 marks? :S

qshyrn

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Re: Question 9 Part C
« Reply #1 on: June 09, 2010, 08:59:27 pm »
Question 9C).....
if i forgot to mention hydrogen bonding in regards to propan-1-ol but mentioned its polarity and dipole dipole bonds and that butane is non polar and has dispersion forces i might get the 3 marks? :S
same with me, but i also stated that dispers Forces are weaker... i think wed get the marks

Davoo!

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Re: Question 9 Part C
« Reply #2 on: June 09, 2010, 09:00:46 pm »
Didn't see the bloody negative.

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andy456

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Re: Question 9 Part C
« Reply #3 on: June 09, 2010, 09:01:38 pm »
i talked about:
the electronegativity of oxygen (dont know why)
the dispersion forces are weak in butane
the dispersion forces in butane are weaker then that of those in propan-1-ol..

hopefully i get at least 1 mark....
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joocoobpootooloo

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Re: Question 9 Part C
« Reply #4 on: June 09, 2010, 09:01:52 pm »
Question 9C).....
if i forgot to mention hydrogen bonding in regards to propan-1-ol but mentioned its polarity and dipole dipole bonds and that butane is non polar and has dispersion forces i might get the 3 marks? :S
same with me, but i also stated that dispers Forces are weaker... i think wed get the marks

i mentioned that too.. i talked about absolutely everything you could talk about except hydrogen bonding :S

tram

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Re: Question 9 Part C
« Reply #5 on: June 09, 2010, 10:27:25 pm »
Question 9C).....
if i forgot to mention hydrogen bonding in regards to propan-1-ol but mentioned its polarity and dipole dipole bonds and that butane is non polar and has dispersion forces i might get the 3 marks? :S
same with me, but i also stated that dispers Forces are weaker... i think wed get the marks

i mentioned that too.. i talked about absolutely everything you could talk about except hydrogen bonding :S

lol exactly tha same....i think dipole dipole should do it imo

joocoobpootooloo

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Re: Question 9 Part C
« Reply #6 on: June 09, 2010, 10:39:28 pm »
hmm i feel slightly better now :D. wow going on vcenotes was the worst thing i could do for my confidence, i thought i mightve gotten full marks.. now il be happy with 71+.

cindyy

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Re: Question 9 Part C
« Reply #7 on: June 10, 2010, 09:36:51 pm »
hmm i feel slightly better now :D. wow going on vcenotes was the worst thing i could do for my confidence, i thought i mightve gotten full marks.. now il be happy with 71+.

i would die for a 71! haha
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superflya

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Re: Question 9 Part C
« Reply #8 on: June 10, 2010, 09:40:39 pm »
Didn't see the bloody negative.

FML.

same -.- i was reading my response and i knew it made no sense at all. but ceebs reading the question again.
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kenhung123

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Re: Question 9 Part C
« Reply #9 on: June 10, 2010, 09:42:19 pm »
hydrogen bonding is a special case of dipole dipole. You probably would get away with it..

joocoobpootooloo

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Re: Question 9 Part C
« Reply #10 on: June 10, 2010, 11:10:23 pm »
fingers crossed :P i went through thinking it was hydrogen bonding in my head in the exam but i convinced myself it wasnt somehow :S

vexx

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Re: Question 9 Part C
« Reply #11 on: June 10, 2010, 11:36:51 pm »
hmm i feel slightly better now :D. wow going on vcenotes was the worst thing i could do for my confidence, i thought i mightve gotten full marks.. now il be happy with 71+.

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scocliffe09

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Re: Question 9 Part C
« Reply #12 on: June 11, 2010, 05:12:58 pm »
hydrogen bonding is a special case of dipole dipole. You probably would get away with it..
I think that if you mentioned that propanol was polar due to the presence of the OH group, and could therefore form dipole-dipole bonds, then I think you might get away with not saying the words hydrogen bonding - but I think it's risky!
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kenhung123

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Re: Question 9 Part C
« Reply #13 on: June 11, 2010, 05:38:49 pm »
Not sure if you need to say polar but its mainly due to strong hydrogen intermolecular bonding which requires high energy (temperature) to break

scocliffe09

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Re: Question 9 Part C
« Reply #14 on: June 12, 2010, 12:07:21 pm »
Not sure if you need to say polar but its mainly due to strong hydrogen intermolecular bonding which requires high energy (temperature) to break
Yessum, but I was suggesting that IF you forgot to say hydrogen bonding, then "very polar" would maybe make up for it?
Just back from spending the year at Oxford. Now onto final year Monash MBBS.

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