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May 21, 2025, 09:24:28 am

Author Topic: brightsky's Noob-tastic Question Thread  (Read 12851 times)  Share 

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iNerd

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Re: brightsky's Noob-tastic Question Thread
« Reply #45 on: March 15, 2011, 08:31:56 pm »
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Can someone clarify, does R^+ / R^- include 0 or not? I remember reading something about this on VN but I can't find it. :/
From my knowledge it's neither. Don't go on me though -.-

luken93

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Re: brightsky's Noob-tastic Question Thread
« Reply #46 on: March 15, 2011, 08:36:32 pm »
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R+ = (0, infinity)
R- = (-infinity, 0)
R+ u R- = R\{0}
R = (-infinity,0) u {0} u (0, infinity)
Source: wolfram
« Last Edit: March 15, 2011, 08:38:26 pm by luken93 »
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iNerd

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Re: brightsky's Noob-tastic Question Thread
« Reply #47 on: March 15, 2011, 08:39:28 pm »
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R+ = (0, infinity)
R- = (-infinity, 0)
R+ u R- = R\{0}
R = (-infinity,0) u {0} u (0, infinity)
Source: wolfram
I'm confused? Doesn't circle bracket mean not included? So was I right? R+ or R-, neither includes 0?

luken93

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Re: brightsky's Noob-tastic Question Thread
« Reply #48 on: March 15, 2011, 08:42:16 pm »
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R+ = (0, infinity)
R- = (-infinity, 0)
R+ u R- = R\{0}
R = (-infinity,0) u {0} u (0, infinity)
Source: wolfram
I'm confused? Doesn't circle bracket mean not included? So was I right? R+ or R-, neither includes 0?
correct
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burbs

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Re: brightsky's Noob-tastic Question Thread
« Reply #49 on: March 15, 2011, 08:44:46 pm »
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yes.

R does not specifically have 0 which is why luken has done U{0}

if a graph has a domain of like [0,infinity) you could say R+ U{0}

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Re: brightsky's Noob-tastic Question Thread
« Reply #50 on: March 15, 2011, 08:53:14 pm »
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It depends, sometimes is taken as non-negative real numbers, while at other times it means positives only.

I would say when answering questions take it as the positive reals and if needed go just to be unambiguous.
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Re: brightsky's Noob-tastic Question Thread
« Reply #51 on: April 07, 2011, 05:14:39 pm »
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yes.

R does not specifically have 0 which is why luken has done U{0}

if a graph has a domain of like [0,infinity) you could say R+ U{0}
is defined to contain 0.

http://en.wikipedia.org/wiki/Real_number
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brightsky

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Re: brightsky's Noob-tastic Question Thread
« Reply #52 on: April 18, 2011, 09:30:17 pm »
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Just another question, how does one reflect any graph about a certain line ax + by + c = 0?
So for instance, if I wanted to reflect the curve y = sqrt(x) about the line y = 1/2 x + 5, what would the equation of the resulting graph be?
Thanks. :)
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Re: brightsky's Noob-tastic Question Thread
« Reply #53 on: April 18, 2011, 09:50:50 pm »
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We did something similar in my maths unit, basically you rotate the line y = 1/2 x + 5 so it's parallel to the x-axis, do the same rotation with the line ax + by + c = 0, reflect it by the rotated line which is parallel to the x-axis (easy) then rotate it back. Not sure if theres a easier method
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Re: brightsky's Noob-tastic Question Thread
« Reply #54 on: April 18, 2011, 10:16:20 pm »
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when rotating(CCW) about another line that makes an angle of with the positive x axis, you apply the matrix transformation:


you would then solve for x, y or eliminate the somehow and put them into the equation y=sqrt(x) and simplify, which im not sure if it can be done or not... maybe someone else with awesome skills can tell you if its possible...
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enpassant

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Re: brightsky's Noob-tastic Question Thread
« Reply #55 on: April 18, 2011, 10:32:16 pm »
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Just another question, how does one reflect any graph about a certain line ax + by + c = 0?
So for instance, if I wanted to reflect the curve y = sqrt(x) about the line y = 1/2 x + 5, what would the equation of the resulting graph be?
Thanks. :)

Using high school maths
find the intersection of the two lines and the angle between them
the reflection is a line through the intersection and make the same angle on the other side

brightsky

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Re: brightsky's Noob-tastic Question Thread
« Reply #56 on: April 19, 2011, 01:44:26 pm »
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Just another question, how does one reflect any graph about a certain line ax + by + c = 0?
So for instance, if I wanted to reflect the curve y = sqrt(x) about the line y = 1/2 x + 5, what would the equation of the resulting graph be?
Thanks. :)

Using high school maths
find the intersection of the two lines and the angle between them
the reflection is a line through the intersection and make the same angle on the other side

Which two lines are you referring to?
when rotating(CCW) about another line that makes an angle of with the positive x axis, you apply the matrix transformation:


you would then solve for x, y or eliminate the somehow and put them into the equation y=sqrt(x) and simplify, which im not sure if it can be done or not... maybe someone else with awesome skills can tell you if its possible...

I saw this matrix on Wikipedia, but I'm not sure how it is derived. And where does the given linear equation about which you reflect it come into play?
We did something similar in my maths unit, basically you rotate the line y = 1/2 x + 5 so it's parallel to the x-axis, do the same rotation with the line ax + by + c = 0, reflect it by the rotated line which is parallel to the x-axis (easy) then rotate it back. Not sure if theres a easier method

Hmm, never thought of that...seems like a good way.

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brightsky

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Re: brightsky's Noob-tastic Question Thread
« Reply #57 on: April 19, 2011, 10:39:55 pm »
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In the notation , what does the second R mean?
Also with the transformation , what do the first and second R^2s mean respectively?
« Last Edit: April 19, 2011, 10:43:51 pm by brightsky »
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luken93

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Re: brightsky's Noob-tastic Question Thread
« Reply #58 on: April 19, 2011, 11:00:39 pm »
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The second R is known as the co-domain, and it specifies the field of y-values that f(x) allows. It's different to the range, because the range is the corresponding values of f(x), whereas R is more of a restriction of values... Oh, and for methods it'll always be R

Can't remember what the R^2 means though XD

EDIT: Read this for R2
« Last Edit: April 19, 2011, 11:05:09 pm by luken93 »
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brightsky

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Re: brightsky's Noob-tastic Question Thread
« Reply #59 on: April 19, 2011, 11:02:03 pm »
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The second R is known as the co-domain, and it specifies the field of y-values that f(x) allows. It's different to the range, because the range is the corresponding values of f(x), whereas R is more of a restriction of values... Oh, and for methods it'll always be R

Can't remember what the R^2 means though XD

ahh makes sense, thanks luken!
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