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May 21, 2025, 08:48:04 pm

Author Topic: brightsky's Noob-tastic Question Thread  (Read 12876 times)  Share 

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kamil9876

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Re: brightsky's Noob-tastic Question Thread
« Reply #60 on: April 19, 2011, 11:22:54 pm »
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EDIT: Read this for R2

I highly doubt it, he probably means just like he means instead of .

It is the set of pairs of real numbers so basically your is a function which sends points on the cartesian plane to some points on a cartesian plane. Example: if was rotation by pi/2 anti-clockwise about origin then   (remember rotation matrices, rings a bell?)
« Last Edit: April 20, 2011, 04:48:33 pm by kamil9876 »
Voltaire: "There is an astonishing imagination even in the science of mathematics ... We repeat, there is far more imagination in the head of Archimedes than in that of Homer."

luken93

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Re: brightsky's Noob-tastic Question Thread
« Reply #61 on: April 19, 2011, 11:43:50 pm »
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EDIT: Read this for R2

I highly doubt it, he probably means just like he means instead of .

It is the set of pairs of real numbers so basically your is a function which sends points on the cartesian plane to some points on a cartesian plane. (example, if was rotation be pi/2 clockwise then  (remember rotation matrices, rings a bell?)
haha, it was the only thing I found and it seemed kinda relevant :P
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pi

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Re: brightsky's Noob-tastic Question Thread
« Reply #62 on: April 20, 2011, 03:03:34 pm »
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In the notation , what does the second R mean?
Also with the transformation , what do the first and second R^2s mean respectively?

I always thought referred to the Cartesian plane (real by real). So, would mean transformations in the Cartesian plane?


EDIT: didn't see kamil's post, my bad :(
« Last Edit: April 20, 2011, 03:12:19 pm by Rohitpi »

TrueTears

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Re: brightsky's Noob-tastic Question Thread
« Reply #63 on: April 24, 2011, 04:51:04 pm »
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In general is just the set of all ordered n-tuples
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brightsky

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Re: brightsky's Noob-tastic Question Thread
« Reply #64 on: April 24, 2011, 05:31:55 pm »
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In general is just the set of all ordered n-tuples

n-tuples?
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Re: brightsky's Noob-tastic Question Thread
« Reply #65 on: April 24, 2011, 05:33:39 pm »
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In general is just the set of all ordered n-tuples

n-tuples?

I too was confused...

From wikipedia:
Quote from: Wikipedia
In mathematics and computer science, a tuple is an ordered list of elements. In set theory, an (ordered) n-tuple is a sequence (or ordered list) of n elements, where n is a positive integer.

...

Tuples are usually written by listing the elements within parentheses "( )" and separated by commas; for example, (2,7,4,1,7) denotes a 5-tuple.

TrueTears

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Re: brightsky's Noob-tastic Question Thread
« Reply #66 on: April 24, 2011, 05:34:36 pm »
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eg, your cartesian coordinates are all 2-tuples (x,y)
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brightsky

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Re: brightsky's Noob-tastic Question Thread
« Reply #67 on: April 24, 2011, 05:40:25 pm »
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eg, your cartesian coordinates are all 2-tuples (x,y)

Are there other 'tuples' that aren't associated with axes? It's hard to imagine, say, a 4-tuple, for instance, if that makes sense..
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TrueTears

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Re: brightsky's Noob-tastic Question Thread
« Reply #68 on: April 24, 2011, 05:45:45 pm »
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The axes you guys relate to 2,3-tuples are just geometric interpretations/functions. The idea of is a concept in its own right, it doesn't need to have any (visible) geometric significance.
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luffy

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Re: brightsky's Noob-tastic Question Thread
« Reply #69 on: April 24, 2011, 06:04:24 pm »
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I may have completely misunderstood you, but are you referring to dimensions?

For example, 2-tuples will produce a 2-dimensional graph. (i.e. 2 axes)

3-tuples will produce 3-dimensional graphs. (3-axes)

So, in theory, n-tuples would produce an n-dimensional graph? (n-axes)

Or am I completely confused?

Andiio

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Re: brightsky's Noob-tastic Question Thread
« Reply #70 on: April 24, 2011, 06:15:43 pm »
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I may have completely misunderstood you, but are you referring to dimensions?

For example, 2-tuples will produce a 2-dimensional graph. (i.e. 2 axes)

3-tuples will produce 3-dimensional graphs. (3-axes)

So, in theory, n-tuples would produce an n-dimensional graph? (n-axes)

Or am I completely confused?

I think you're right, because if we have a 2-tuple, i.e. (x,y) ordered pair, we will naturally have 2 axes (an 'x' axis and 'y' axis) formed along with it.
Not sure if I'm right though :P
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TrueTears

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Re: brightsky's Noob-tastic Question Thread
« Reply #71 on: April 24, 2011, 06:23:51 pm »
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I may have completely misunderstood you, but are you referring to dimensions?

For example, 2-tuples will produce a 2-dimensional graph. (i.e. 2 axes)

3-tuples will produce 3-dimensional graphs. (3-axes)

So, in theory, n-tuples would produce an n-dimensional graph? (n-axes)

Or am I completely confused?
Depends on your definition of dimensions, the general definition is that the dimension of a vector space (in this case ) is the number of vectors that make up a basis in that vector space.

Thus we have

There is no such thing that: "n-tuples produce a n-dimensional graph", the italic terms you used are too informal and not precise enough.

The correct way to interpret is that the dimension of the vector space is n.



I suggest you guys just treat it as notation for now and don't worry about the details, you need linear algebra knowledge to understand what I mean. Thinking too deeply at this stage without fundamentals will only confuse you :)
« Last Edit: April 24, 2011, 06:33:15 pm by TrueTears »
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luffy

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Re: brightsky's Noob-tastic Question Thread
« Reply #72 on: April 24, 2011, 06:31:59 pm »
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I may have completely misunderstood you, but are you referring to dimensions?

For example, 2-tuples will produce a 2-dimensional graph. (i.e. 2 axes)

3-tuples will produce 3-dimensional graphs. (3-axes)

So, in theory, n-tuples would produce an n-dimensional graph? (n-axes)

Or am I completely confused?
Depends on your definition of dimensions, the general definition is that the dimension of a vector space (in this case ) is the number of basis in that vector space.

Thus we have

There is no such thing that: "n-tuples produce a n-dimensional graph", the italic terms you used are too informal and not precise enough.

The correct way to interpret is that the dimension of the vector space is n.



I suggest you guys just treat it as notation for now and don't worry about the details, you need linear algebra knowledge to understand what I mean. Thinking too deeply at this stage without fundamentals will only confuse you :)

Haha - Fair enough. I was just using colloquial language to understand it.

I think you just spiked everyone's interest by the mention of the word "tuples".

Maths gets amazingly repetitive, and so we seek completely new knowledge to satisfy our 'hunger' :P

TrueTears

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Re: brightsky's Noob-tastic Question Thread
« Reply #73 on: April 24, 2011, 06:42:18 pm »
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That's great! I encourage you guys to read further if you have the time. If you are interested to really delve deeper, please take time to read the book, download link is below.

http://www.megaupload.com/?d=E8WXXE2Q
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brightsky

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Re: brightsky's Noob-tastic Question Thread
« Reply #74 on: April 30, 2011, 10:56:21 pm »
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What's the general idea behind how to prove concurrency using vectors?
More specifically, how do you prove that the medians of a triangle are concurrent?
And from there, how do you prove that the centroid divides each median in the ratio 2:1? (Vectors or an easier way using simple geometry)
« Last Edit: April 30, 2011, 11:02:28 pm by brightsky »
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