MAV 2010 Exam 2

[fady_22]

What the hell is nSolve.

Numerical solve.
It's a faster way of solving when you need a numerical solution (but only provides one solution).

[Blakhitman]

Wont pressing ctr enter yield the same solution?

[fady_22]

It's usually much faster.
Especially if you have the TI 89 (I'm assuming you have the NSpire), where some equations take about 5 minutes (if not more) to solve.

[Blakhitman]

Oh fair enough, so it's mainly used for the huge equations then.

Thanks.

[Jdog]

do you guys have the solutions for this paper?

[Stroodle]

I'm pretty sure they're here: http://vcenotes.com/forum/index.php/topic,29541.0.html

[Jdog]

cheers, hah i just did the exam as a practice one,

i think question 14 is wrong, i think the answer is 2 not 2.2 anybody agree,

i think the error in the solutions is,

they put .2*1 + .35 * 2 + .3*3 + 4 * .1

the last bit of it should be 4* .05,

cuz they showed r to be .05

[Jdog]

another error 

question one part G,  they gave the intersection point to be (8.75, 60) it should be (8.25, 60)

[Jdog]

cross out the first erroor i realised my mistake

[Stroodle]

I think you're right about the second error; can vaguely remember it.

[thushan]

cheers, hah i just did the exam as a practice one,

i think question 14 is wrong, i think the answer is 2 not 2.2 anybody agree,

i think the error in the solutions is,

they put .2*1 + .35 * 2 + .3*3 + 4 * .1

the last bit of it should be 4* .05,

cuz they showed r to be .05

r is 0.05, but the probability of X being 4 was 2r, so you put 4*0.1

[Jdog]

yeah dude ,

i realised ,,

HAHA if only we knew about this before hand. LOL

[Blakhitman]

Can someone please explain Q. 17?

I assume you all have the exam, so no need to put question.

[stonecold]

Draw them all in the CAS.  Doesn't take too long to just change the few numbers.  You have to choose the graph at which the y-intercept is less than 0, and the point of undefined gradient has to exist at (3,1)

Remember as it is an x^1/3, there will be a point of undefined gradient, which means the tangent will be undefined.  The normal however, will be a horizontal line, with a gradient of 0, and hence the normal has the equation y=1.

[Whatlol]

*deleting what i just said*