QUICK GRAPHS&RELATIONS Q

[gold104]

Could somebody please show me how to map lines such as y=6.4x, y=0.5x etc..

Example shown in the 2008vcaa exam 2 (q3 bi.) it asks to draw y=1.5x.

I have no idea. If someone has time to explain ill be stoked! thanks

[_avO]

You sub in 2 or 3 values (far apart) and plot it on the graph, then draw a line through it

Easiest way is to sub x = 10, gets y = 64 and plot that and draw a line from that point to the origin (0,0)

[gold104]

You sub in 2 or 3 values (far apart) and plot it on the graph, then draw a line through it

Easiest way is to sub x = 10, gets y = 64 and plot that and draw a line from that point to the origin (0,0)

thanks but im still not following you 100%. could you show me eactly what you did for that question with the subs? Sorry, its probably a good explanation, im not great at this aspect of the module obviously

[_avO]

well if there is an equation in the form y=mx (eg. y=0.5x), you know that the line must pass through (0,0). Then you sub in any appropriate value (depending on what it is you're talking about) such as x=10, get the y value (10,5) and put that point on the graph, then map a line through both points all the way through

[gold104]

Awesome. got it, thanks for taking the time to explain

Could very well be in tomorrows exam, cheers!

[_avO]

Most likely a 'fit the regression line' on the graph sorta question

[superstar1]

so in fit the regression line you will have to sub points in the given regression line.
?

[_avO]

if you want complete accuracy then yes