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July 22, 2025, 12:11:29 am
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Author Topic: TSFX 2010  (Read 6149 times)  Share 

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scocliffe09

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Re: TSFX 2010
« Reply #15 on: November 09, 2010, 07:19:15 pm »
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Quote from: stonecold on November 09, 2010, 07:05:34 pm
Is this exam worth doing?


I think it is, because it illustrates some interesting points/ideas. Just don't take it to seriously if you do do it and don't let it affect your confidence. Irena writes so many questions that some of them can occasionally be a bit...off the mark.
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Blakhitman

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Re: TSFX 2010
« Reply #16 on: November 09, 2010, 07:20:20 pm »
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Gotta finish those tutes before Thursday Mao :P
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Martoman

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Re: TSFX 2010
« Reply #17 on: November 10, 2010, 12:56:11 am »
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gahhhh not 2010, 2008 exam

Platinum electrodes are suspended into a 500ml solution containing the following ions

Ag+, Cu2+, Al3+, Ni2+. If the current was passed through the cell at constant voltage of 1.4, the last metal to be depositied onto the cathode would be

Ag
Cu
Al
Ni


So obviously Al is not, its below water. I say nickel but they say: To deposit Ni, and EMF of 1.46 V is required.. where did they get this EMF from?

in short their answer is Cu
« Last Edit: November 10, 2010, 01:03:08 am by Martoman »
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samiira

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Re: TSFX 2010
« Reply #18 on: November 10, 2010, 02:09:29 am »
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Quote from: Martoman on November 10, 2010, 12:56:11 am
gahhhh not 2010, 2008 exam

Platinum electrodes are suspended into a 500ml solution containing the following ions

Ag+, Cu2+, Al3+, Ni2+. If the current was passed through the cell at constant voltage of 1.4, the last metal to be depositied onto the cathode would be

Ag
Cu
Al
Ni


So obviously Al is not, its below water. I say nickel but they say: To deposit Ni, and EMF of 1.46 V is required.. where did they get this EMF from?

in short their answer is Cu

i tried to find a reason where they got 1.46 but i failed.. i dnno mayb question seems dodgy.. i wud say Ni aswell..
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samiira

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Re: TSFX 2010
« Reply #19 on: November 10, 2010, 02:12:40 am »
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btw is the emf calculated like this 0.8+0.34+0.23 ..??
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Martoman

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Re: TSFX 2010
« Reply #20 on: November 10, 2010, 02:28:08 am »
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I have no idea actually...
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crayolé

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Re: TSFX 2010
« Reply #21 on: November 10, 2010, 03:57:11 am »
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Does it come from
O2 + 4H+ + 4e- ---> 2H2O       +1.23V

Ni2+ + 2e- ---> Ni(s)              -0.23V

-.23 + (-1.23) = -1.46 V
« Last Edit: November 10, 2010, 03:59:30 am by crayola »
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Mao

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Re: TSFX 2010
« Reply #22 on: November 10, 2010, 03:08:06 pm »
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Quote from: Blakhitman on November 09, 2010, 07:20:20 pm
Gotta finish those tutes before Thursday Mao :P

haha, yeah right... I will endeavour to finish those by next year. I totally underestimated how much work I had. I've finished two slabs of mother in the last 4 weeks. TWO SLABS. (48 cans, that's right)
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Blakhitman

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Re: TSFX 2010
« Reply #23 on: November 10, 2010, 03:09:31 pm »
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Mother is disgusting.
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samiira

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Re: TSFX 2010
« Reply #24 on: November 10, 2010, 03:10:48 pm »
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Quote from: Blakhitman on November 10, 2010, 03:09:31 pm
Mother is disgusting.

yeh i hate mother.. i am all for 'V' .
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98.40_for_sure

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Re: TSFX 2010
« Reply #25 on: November 10, 2010, 03:17:13 pm »
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What's wrong with mother? just finished 2 slabs of V and 1 slab of mother right in time for exam period finish :D
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Martoman

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Re: TSFX 2010
« Reply #26 on: November 10, 2010, 03:55:03 pm »
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still don't really get this..

Similarly, if you have a voltage of 2V why can't water be deposited at the cathode of an electrolytic cell ala KBT tsmania jones question?
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crayolé

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Re: TSFX 2010
« Reply #27 on: November 10, 2010, 08:48:02 pm »
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I was always taught that  in order to power a non-spontaneous reaction, you're going to need higher voltage than the EMF of both.
For the Tassy Jones one, electrolysis of water requires 1.23 - (-0.83) = 2.06V for the non-spontaneous reaction to go ahead, any lower and its going to do shit all
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3Xamz

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Re: TSFX 2010
« Reply #28 on: November 10, 2010, 08:51:18 pm »
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Quote from: crayola on November 10, 2010, 03:57:11 am
Does it come from
O2 + 4H+ + 4e- ---> 2H2O       +1.23V

Ni2+ + 2e- ---> Ni(s)              -0.23V

-.23 + (-1.23) = -1.46 V


It's -.23 - (-1.23) = 1.46v.

If you get a negative EMF then the reaction won't be spontaneous and you won't have current through it.
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