cone... correct me if i'm wrong.

[chrisjb]

Hello Maths Methods CAS,

I'm not doing methods, but I had a look at your 'cone of death' just before and it seem to me that there was a much more simple way to solve it than you guys did... you can do it graphicaly.

Because of the shape of the cone, the cylinder is held in such a way that when the height is 0, the radius is 2, and when the radius is 0 the height is 5. This gives you this:

Height: 0   Radius: 2
Height: 5   Radius: 0

You can then use those to plot a graph (the fist set of numbers being x1, y1 and the seccond set beign x2, y2)

The equation of that graph (using y=mx+c) is (with h on the y axis): h= -5/2 r +5

This is essentialy the same as the equation you find using your simmilar triangles method isn't it?

I may be completely wrong, so correct me if I am... but it seems to be a more simple way.

[Whatlol]

let us rest in peace )=

p.s seems to work

[chrisjb]

hehe... sorry, I figgured all your wounds would have healed by now

[Whatlol]

hehe... sorry, I figgured all your wounds would have healed by now

hehe they are still raw )=

[ninbam1k]

LOL i like your location Whatlol

[schnappy]

Congrats, you've done similar triangles from first principles...

[carolynt]

let us rest in peace )=

p.s seems to work

Awwwww :/

[TrueTears]

Hello Maths Methods CAS,

I'm not doing methods, but I had a look at your 'cone of death' just before and it seem to me that there was a much more simple way to solve it than you guys did... you can do it graphicaly.

Because of the shape of the cone, the cylinder is held in such a way that when the height is 0, the radius is 2, and when the radius is 0 the height is 5. This gives you this:

Height: 0   Radius: 2
Height: 5   Radius: 0

You can then use those to plot a graph (the fist set of numbers being x1, y1 and the seccond set beign x2, y2)

The equation of that graph (using y=mx+c) is (with h on the y axis): h= -5/2 r +5

This is essentialy the same as the equation you find using your simmilar triangles method isn't it?

I may be completely wrong, so correct me if I am... but it seems to be a more simple way.

Yup exactly what schnappy said, "similar triangles" is just basically algebra in disguise

[carolynt]

Yep, did that.