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February 25, 2026, 07:46:06 pm

Author Topic: ajshfgsjkhgf vectors question  (Read 1894 times)  Share 

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BubbleWrapMan

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ajshfgsjkhgf vectors question
« on: December 04, 2010, 07:45:26 pm »
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ABCD is a trapezium with AB parallel to DC. X and Y are midpoints of AD and BC respectively.

(It's laid out something like this)

  DC
 X  Y
A    B

a) Express (directed line segment) XY in terms of a and b where (directed line segment) AB = a and (directed line segment) DC = b
b) Show that XY is parallel to AB
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BubbleWrapMan

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Re: ajshfgsjkhgf vectors question
« Reply #1 on: December 04, 2010, 08:02:50 pm »
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I was thinking that, but the answer says (1/2)(a + b) which makes me think I'm missing something.
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cipherpol

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Re: ajshfgsjkhgf vectors question
« Reply #2 on: December 04, 2010, 08:04:05 pm »
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let and

or

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98.40_for_sure

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Re: ajshfgsjkhgf vectors question
« Reply #3 on: December 04, 2010, 08:06:24 pm »
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Ahhah totally forgot you could define new vectors
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Re: ajshfgsjkhgf vectors question
« Reply #4 on: December 04, 2010, 08:09:12 pm »
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Ah nice. Thanks everyone. ^^
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Re: ajshfgsjkhgf vectors question
« Reply #5 on: December 04, 2010, 08:11:03 pm »
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Hey brightsky, why is a.b and a.a = 0?
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Re: ajshfgsjkhgf vectors question
« Reply #6 on: December 04, 2010, 08:20:01 pm »
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I would have thought you'd just say something like

Since a and b are parallel, XY must be parallel to both, since a scalar multiplication of the sum of two parallel lines does not change the direction.
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Re: ajshfgsjkhgf vectors question
« Reply #7 on: December 04, 2010, 08:21:53 pm »
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AB = a
since a = kb, XY = 1/2(a+ka) = 1/2(k+1)a

thus parallel?
« Last Edit: December 04, 2010, 08:24:24 pm by 99.95_for_sure »
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Re: ajshfgsjkhgf vectors question
« Reply #8 on: December 04, 2010, 08:25:29 pm »
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Yeah. You're allowed to put it in words though aren't you? I've done it in the past.
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Re: ajshfgsjkhgf vectors question
« Reply #9 on: December 04, 2010, 08:27:53 pm »
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Show that XY is parallel to AB.
Which means mathematical proof not 'explain'
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Re: ajshfgsjkhgf vectors question
« Reply #10 on: December 04, 2010, 08:36:52 pm »
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Hmm. Good point. :P
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Re: ajshfgsjkhgf vectors question
« Reply #11 on: December 04, 2010, 08:41:30 pm »
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Hey brightsky, why is a.b and a.a = 0?

Woops, I was thinking cross product. Listen to 99.95_for_sure. :p
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