Toolbox question

[MBBS]

I thought of that too, it asks you however to HENCE find the exact values of sin ( 15 ) ...

I would assume you are not allowed to use sin 15 in the first part of the question then.

[Greatness]

Couldn't we use Sin(45-30)
and then do:
sin(45)cos(30)-cos(45)sin(30)?

what andiio said is probably the easiest way of doing it
Simply using sin(z) = sin(15) is much easier and less complicated; it is only simple trig anyways

[Andiio]

I thought of that too, it asks you however to HENCE find the exact values of sin ( 15 ) ...

I would assume you are not allowed to use sin 15 in the first part of the question then.

Tony, did you get my text?

Oh and, do you mean part (a)? You don't need to use sin(15) to find the values of the pronumerals o_o

[BubbleWrapMan]

I would say my method was what they were looking for since the question asks to find the pronumerals, plus the cos(x - y) thing doesn't show up until chapter 3.

[golden]

Could anyone explain how to do questions 3, 4 or 5 from the Extended Response questions in the Toolbook review (chapter 1)? Thanks.