A soluble fertilister contains phosphorus in the form of phosphate ions. To determine the phosphate content by gravimetric analysis, 5.97 g of the fertiliser powder was completely dissolved in water to make a volume of 250.0 mL. A 20.00 mL volume of this solution was pipetted into a conical flask and the phosphate ions in the solution were precipitated as MgNH4PO4. The precipitate was filtered, washed with water and then converted by heating into Mg2P2O7. THe mass of it was 0.0352g.
If the conical flask had been previously washed with water but not dried, indicate the likely effect on the calculated percentage of phosphate ions in the fertiliser.
The answer says 'no effect on calculated result.' But, since there's water left over in the conical flask, wouldn't the concentration of phosphate be less than what I calculated, since I used 20 mL as my volume and the real volume is higher than that? Wouldn't the calculated result be too low?