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February 27, 2026, 10:22:35 pm

Author Topic: Inverse trig functions  (Read 2175 times)  Share 

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pi

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Inverse trig functions
« on: March 02, 2011, 07:00:19 pm »
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Do we need to know the inverse of the reciprocal trig functions too?
eg. Sketch

huaxiadragon

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Re: Inverse trig functions
« Reply #1 on: March 02, 2011, 07:06:13 pm »
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I'm pretty dam sure you don't. I've done a crap load of exam papers last year and that wasn't anywhere on them nor the course.

Ring VCAA and give them a flurry of insults if they ever appear.

They SHOULD NOT appear anyway.

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pi

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Re: Inverse trig functions
« Reply #2 on: March 02, 2011, 07:08:08 pm »
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Ok, thanks. Just wondering because my teacher mentioned it to me after class, and the inverse reciprocal ones look really 'different'.

Thanks again.

vea

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Re: Inverse trig functions
« Reply #3 on: March 04, 2011, 03:44:14 pm »
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You definitely do not need to know about them.
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pi

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Re: Inverse trig functions
« Reply #4 on: March 04, 2011, 03:58:23 pm »
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You definitely do not need to know about them.

Thats a shame, they looked cool...

Thanks though

Mao

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Re: Inverse trig functions
« Reply #5 on: March 04, 2011, 05:22:31 pm »
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Well it shouldn't be too much of a stretch anyways.

-Draw out the reciprocal function, restricts its domain such that it is one-to-one
-Draw the inverse
-Apply transformations

Which seems straight forward, but might take a long time to do because it can get messy.
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pi

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Re: Inverse trig functions
« Reply #6 on: March 04, 2011, 06:08:55 pm »
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Those are the exact steps I used Mao!

But, should be need to know how to solve inverse reciprocals (if not graphing), eg: for x?

(this is considerably easier than graphing though)

Mao

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Re: Inverse trig functions
« Reply #7 on: March 04, 2011, 06:45:24 pm »
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Those are the exact steps I used Mao!

But, should be need to know how to solve inverse reciprocals (if not graphing), eg: for x?

(this is considerably easier than graphing though)

again, not a huge stretch from normal solving. I don't see why you should worry too much.
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pi

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Re: Inverse trig functions
« Reply #8 on: March 04, 2011, 06:46:30 pm »
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again, not a huge stretch from normal solving. I don't see why you should worry too much.

Thats true, thanks. Just a bit worried because I have a test on this on Tuesday...

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Re: Inverse trig functions
« Reply #9 on: March 09, 2011, 09:34:18 pm »
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Sec^-1 graph showed up on our trig SAC, lol
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pi

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Re: Inverse trig functions
« Reply #10 on: March 11, 2011, 05:47:24 pm »
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Sec^-1 graph showed up on our trig SAC, lol

SAME HERE ON MY TEST! Although it was a 'bonus' question, so we had to prove the domain and range for the original sec^-1 graph (one-to-one, including zero, etc.).

Good test though.