Question regarding KBT exam question 2d)
Does erucic acid (C66 H126 O6) have any carbon-carbon double bonds? If so, how many?
Working out the no. of double bonds with DBE = 66 - 126/2 + 1 = 4
Therefore there are 3 C=C double bonds and one C=O double bond.
However, the answers work with the empirical formula of euric acid.
Working with DBE again but with the empirical formula would give 2 --> One C=C double bond and one C=O double bond?...
Question is... to work out the number of double bonds, do we use the empirical formula or the molecular formula? Because they'll give different answers....
Edit: Oops, forgot that there are 6 oxygens in the molecular formula of erucic acid.. does that mean there are 3 C=O? Hence one C=C double bond?
If so, that works out right.... hm.