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August 22, 2025, 03:36:08 pm
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Author Topic: Esterification  (Read 3563 times)  Share 

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RobM8

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Esterification
« on: June 04, 2011, 03:35:35 pm »
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Distinction between esterification and transesterification?
I have only seen the sates of the carboxylic acid, the alcohol and the resulting ester as (l), would you be incorrect to put the states of the produced ester, and the reacted carboxylic acid and alcohol as (aq) ?
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funkyducky

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Re: Esterification
« Reply #1 on: June 04, 2011, 04:29:35 pm »
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It would be ok to write the carb acid and alcohol as aqueous, but not the ester.
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luken93

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Re: Esterification
« Reply #2 on: June 04, 2011, 04:30:05 pm »
+1
Esterification = Forming an Ester between a Carboxyl and an Alkanol, emitting water in the process
Trans = Swapping one ester with another, ie triglyceride -> 3x methyl esters.
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RobM8

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Re: Esterification
« Reply #3 on: June 04, 2011, 09:23:16 pm »
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Thanks lads
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Aurelian

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Re: Esterification
« Reply #4 on: June 05, 2011, 10:59:24 am »
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Quote from: funkyducky on June 04, 2011, 04:29:35 pm
It would be ok to write the carb acid and alcohol as aqueous, but not the ester.

That is not correct.

Esterification does not occur in the presence of water; you cannot label the carboxylic acid or the alkanol as aqueous. This is not a reaction in aqueous solution, even though water may be *produced* by it.

The carboxylic acid, alkanol and ester would all be either (l) or (s).
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golden

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Re: Esterification
« Reply #5 on: June 05, 2011, 06:01:22 pm »
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Quote from: Aurelian on June 05, 2011, 10:59:24 am
Quote from: funkyducky on June 04, 2011, 04:29:35 pm
It would be ok to write the carb acid and alcohol as aqueous, but not the ester.

That is not correct.

Esterification does not occur in the presence of water; you cannot label the carboxylic acid or the alkanol as aqueous. This is not a reaction in aqueous solution, even though water may be *produced* by it.

The carboxylic acid, alkanol and ester would all be either (l) or (s).

Hmm. So if we had:
Ethanoic acid and ethanol, we would make the liquids and the product (ester) a liquid also even though water is 'produced' in the course?
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Aurelian

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Re: Esterification
« Reply #6 on: June 05, 2011, 06:50:47 pm »
+1
Quote from: golden on June 05, 2011, 06:01:22 pm
Quote from: Aurelian on June 05, 2011, 10:59:24 am
Quote from: funkyducky on June 04, 2011, 04:29:35 pm
It would be ok to write the carb acid and alcohol as aqueous, but not the ester.

That is not correct.

Esterification does not occur in the presence of water; you cannot label the carboxylic acid or the alkanol as aqueous. This is not a reaction in aqueous solution, even though water may be *produced* by it.

The carboxylic acid, alkanol and ester would all be either (l) or (s).

Hmm. So if we had:
Ethanoic acid and ethanol, we would make the liquids and the product (ester) a liquid also even though water is 'produced' in the course?

Yes that's right :)
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pi

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Re: Esterification
« Reply #7 on: June 05, 2011, 06:54:46 pm »
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Quote from: golden on June 05, 2011, 06:01:22 pm
Quote from: Aurelian on June 05, 2011, 10:59:24 am
Quote from: funkyducky on June 04, 2011, 04:29:35 pm
It would be ok to write the carb acid and alcohol as aqueous, but not the ester.

That is not correct.

Esterification does not occur in the presence of water; you cannot label the carboxylic acid or the alkanol as aqueous. This is not a reaction in aqueous solution, even though water may be *produced* by it.

The carboxylic acid, alkanol and ester would all be either (l) or (s).

Hmm. So if we had:
Ethanoic acid and ethanol, we would make the liquids and the product (ester) a liquid also even though water is 'produced' in the course?
Remember H2SO4 catalyst is also liquid, got marked down for writing (aq)
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jane1234

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Re: Esterification
« Reply #8 on: June 05, 2011, 07:29:48 pm »
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Is there any general rules with writing states? Usually I just guess... ???
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luken93

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Re: Esterification
« Reply #9 on: June 05, 2011, 07:55:52 pm »
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Quote from: jane1234 on June 05, 2011, 07:29:48 pm
Is there any general rules with writing states? Usually I just guess... ???
Amen to that hahaha
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scocliffe09

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Re: Esterification
« Reply #10 on: June 06, 2011, 10:38:31 pm »
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Quote from: jane1234 on June 05, 2011, 07:29:48 pm
Is there any general rules with writing states? Usually I just guess... ???
For the reaction pathways, learn them.
Otherwise, use your knowledge of the molecules' properties to help you guess :)
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VivaTequila

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Re: Esterification
« Reply #11 on: June 08, 2011, 09:18:38 pm »
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Quote from: scocliffe09 on June 06, 2011, 10:38:31 pm
Quote from: jane1234 on June 05, 2011, 07:29:48 pm
Is there any general rules with writing states? Usually I just guess... ???
For the reaction pathways, learn them.
Otherwise, use your knowledge of the molecules' properties to help you guess :)

This, but as a general rule when anything is in the presence of water use H2O as a liquid and anything else as aq. Otherwise, know your precipitates in reactions, like AgCl and PbEverything.
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rena-bena

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Re: Esterification
« Reply #12 on: June 08, 2011, 11:03:28 pm »
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Alcohol and carb acid MUST be in liquid state. So is the ester. Otehrwise - no marks.
Chem Teacher.
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scocliffe09

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Re: Esterification
« Reply #13 on: June 08, 2011, 11:53:49 pm »
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Quote from: VivaTequila on June 08, 2011, 09:18:38 pm
Quote from: scocliffe09 on June 06, 2011, 10:38:31 pm
Quote from: jane1234 on June 05, 2011, 07:29:48 pm
Is there any general rules with writing states? Usually I just guess... ???
For the reaction pathways, learn them.
Otherwise, use your knowledge of the molecules' properties to help you guess :)

This, but as a general rule when anything is in the presence of water use H2O as a liquid and anything else as aq. Otherwise, know your precipitates in reactions, like AgCl and PbEverything.
yeah this general rule is not great... see rena-bena's post...
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luken93

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Re: Esterification
« Reply #14 on: June 09, 2011, 08:34:29 am »
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Okay, can we maybe just write some general rules down for these sorts of things.

Combustion:
Alkane(g) + O2(g)  -->   CO2(g) + H2O(g)

Esterification:
Alkanol (l) + Carboxylic Acid (l)  - H2SO4(l) ->  Ester (l) + H2O(l)

Hydrogenation:
Alkene(g) + H2(g)  - Ni ->  Alkane(g)

Halogenation:
Alkane(g) + Cl2(g)  - UV Light ->  Chloroalkane(g) + HCl(g)

Alkanol(aq)  - PCl5 ->  Chloroalkane(g)

Chloroalkane(g) - NaOH(aq) -> Alkanol(g) + NaCl(g)

Alkanol(aq) - Cr2O72-(aq) / H+(aq) -> Carboxylic Acid(aq)

Alkene(g) + H2O(g)  - H3PO4(aq) -> Alkanol(aq)

Feel free to clean up any of the ones I have mentioned, but that's what I've got in my notes...



« Last Edit: June 09, 2011, 08:49:32 am by luken93 »
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