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June 17, 2024, 04:57:45 am

Author Topic: Predictions for this year's Unit 3 Exam  (Read 9443 times)  Share 

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dopplereffect

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Re: Predictions for this year's Unit 3 Exam
« Reply #15 on: June 10, 2011, 02:03:34 pm »
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I was speaking to one of the physics teachers at my school and she said that there will a lot more definitions than calculations relative to past years so that girls will be more better off than previously, no joke.

jinny1

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Re: Predictions for this year's Unit 3 Exam
« Reply #16 on: June 10, 2011, 02:18:19 pm »
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How wud ur teacher know???
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soopertaco

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Re: Predictions for this year's Unit 3 Exam
« Reply #17 on: June 10, 2011, 02:20:14 pm »
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I was speaking to one of the physics teachers at my school and she said that there will a lot more definitions than calculations relative to past years so that girls will be more better off than previously, no joke.
statement of fact or speculation?
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xZero

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Re: Predictions for this year's Unit 3 Exam
« Reply #18 on: June 10, 2011, 02:24:01 pm »
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Bank curves involving friction to throw people off and stop people from using a pre-rearranged forumla. Couple of force diagrams and some tricky question asking you to find tension between two objects like question 1 or 2 from 2010 exam. Electronics they might have a question with short circuit and special relativity should be easier given last year was pretty hard.
« Last Edit: June 10, 2011, 03:46:17 pm by xZero »
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thushan

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Re: Predictions for this year's Unit 3 Exam
« Reply #19 on: June 10, 2011, 02:27:24 pm »
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Thoughts on predicted difficulty of this year's exam, measured by A+ cutoff out of 90? I'm going for something <80, so say 78?
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Re: Predictions for this year's Unit 3 Exam
« Reply #20 on: June 10, 2011, 03:35:02 pm »
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Bank curves involving friction to throw people off to stop people from using a pre-rearranged forumla.

How would you go about solving something like that?

My teacher gave us a formula but not sure if it actually works or not.

Fnet = Frcos(theta) + Nsin(theta)
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xZero

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Re: Predictions for this year's Unit 3 Exam
« Reply #21 on: June 10, 2011, 03:46:00 pm »
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What is this... they have a formula for everything :( Assuming Fr = Friction then yeah that formula works pefectly although I suggest drawing a free body diagram to fully understand the situation.
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ttn

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Re: Predictions for this year's Unit 3 Exam
« Reply #22 on: June 10, 2011, 03:53:14 pm »
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Oh, but I'm a bit confused about the N bit, teacher says it's just the weight?
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xZero

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Re: Predictions for this year's Unit 3 Exam
« Reply #23 on: June 10, 2011, 04:26:44 pm »
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N is the normal force, on a banked curves N =/= weight force
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ttn

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Re: Predictions for this year's Unit 3 Exam
« Reply #24 on: June 10, 2011, 04:29:51 pm »
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So it's going to be

Fnet = Frcos(theta) + mgcos(theta)sin(theta)??
     
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cranberry

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Re: Predictions for this year's Unit 3 Exam
« Reply #25 on: June 10, 2011, 04:47:31 pm »
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^^ stop, ur confusing me lol :P
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ttn

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Re: Predictions for this year's Unit 3 Exam
« Reply #26 on: June 10, 2011, 05:28:44 pm »
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So I just scanned the diagram from the Jacaranda text book.

Looks like the actual 'N' is mgcos(theta)?
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yawho

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Re: Predictions for this year's Unit 3 Exam
« Reply #27 on: June 10, 2011, 06:08:41 pm »
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explain the advantage of banking a curved road

cohen

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Re: Predictions for this year's Unit 3 Exam
« Reply #28 on: June 10, 2011, 06:15:11 pm »
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From my help sheet; Banking the road eliminates the need for a sideways frictional force and allows the car to travel faster without skidding out of the circular path,

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Re: Predictions for this year's Unit 3 Exam
« Reply #29 on: June 10, 2011, 06:24:10 pm »
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you stated the advantage, but how do you explain it?