General questions thread (fk u vcaa)

[Asx4Life]

I think you meant carrier wave? I wrote it was the LED's light.
For the graph I drew it still pointy, because power is proportional to current?
Now I just realised the voltage across it will change also... so dunno.

i drew it curvy lol, i think im wrong =(.

[thatisanote]

I think you meant carrier wave? I wrote it was the LED's light.
For the graph I drew it still pointy, because power is proportional to current?
Now I just realised the voltage across it will change also... so dunno.

I did straight lines and not hitting the x-axis

[davidle_10]

I did the exact thing as thatisanote

[examsman]

Motion:
Q1 net force = 1250 N
Q2 tension = 1000 N
Q3 how far = 6.25 m
Q4 net force = 3375 N
Q5 vector sum of the two forces gives the net force
Q6 banked track angle = 48.4 deg
Q7 block C on block B = 1.5 N, Newton's third law
Q8 zero, in free fall, gravity is the only force on each block, no other interacting forces
Q9 12.2 m/s
Q10 zero app weight, Mel is also in free fall and .: no reaction force on Mel
Q11 app weight = 721 N
Q12 t approx 2.89 s
Q13 max height 10.4 m
Q14 momentum = 960 kg m/s
Q15 friction = 160 N
Q16 10=k0.3, k = 33.3
Q17 D
Q18 C
Q19 B
Q20 F
Q21 grav field = 10 N/kg
Q22 mass of visitor planet = 1.35 X10^20 kg
Q23 period = 3.2 X 10^6 s

Ele photo
Q1 2+4/3=3.3 Ohms
Q2 I(B)=2 A
Q3 V(A)=6 V
Q4 P(D)=2 W
Q5 resistance = 1500 ohms at 20 deg
Q6 switching circuit parallel to 4500 ohms resistor
Q7 resistance = 40 ohms
Q8 voltage across 2k ohm resistor = 8.0 V
Q9 same shape but inverted, greater than 0.
Q10 carrier wave is the light wave emitted by LED when the sliding contact is in the middle of the var resistor. The brightness changes ( modulation) when the sliding contact moves
Q11 same shape as the input and non-inverting, amplitude 2 V
Q12 clipping when input is outside -10 to 10 mV, max output +/- 4V

S & materials
Q1 C
Q2 C
Q3 B
Q4 B
Q5 D
Q6 B
Q7 D
Q8 C
Q9 C
Q10 A
Q11 A
Q12 B

[jinny1]

In the materials and structure MC.

What was the tension of the rope wheere there was a sign hanging off it

it was like either 40,60,400,560 newtons..

[Romperait]

I think it was 400N.

[examsman]

confirming 400,

Could somebody please tell me what they thinkabout the suggested solution for  Motion: 9,13. S and M: 6

[ttn]

i drew it pointy, do you mean the voltage across the LED? that wont change... its a diode

Oh yeah, forgot about that lol. Guess I drew it right then.

[jinny1]

why was it 400???

the weight of the sign was 40kg, but wasnt it partly supported by the strut?

[examsman]

I can't be bothered explaining but it was definitely 400N. you're looking for the component acting horizontally, work from there, not vertically, with the brightness graph, it was definitely NOT pointy. it's a modulated signal and thus it can't be pointy lol.

[ttn]

But the modulated signal was the brightness of the LED, not the actual light wave. And power is proportional to current, so the power will increase/decrease linearly?

[jinny1]

I can't be bothered explaining but it was definitely 400N. you're looking for the component acting horizontally, work from there, not vertically, with the brightness graph, it was definitely NOT pointy. it's a modulated signal and thus it can't be pointy lol.

crap mine is pointy...

[Lols123]

was q10 on s and m, a beam or cantilever

[dopplereffect]

Q7 block C on block B = 1.5 N, Newton's third law

Isn't it 1N because the block has a mass of 0.1kg? Or did I misread the weights?

[jinny1]

yea i thought it was 1N?