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July 04, 2025, 02:08:41 pm

Author Topic: Help please? :) [unit 2]  (Read 1666 times)  Share 

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kamil9876

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Re: Help please? :) [unit 2]
« Reply #15 on: July 07, 2011, 10:49:56 am »
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Most likely in vce it does have an inverse so for your purposes you should probably ignore me.

Just saying that according to the mathematical community it wouldn't. Check the definition here. Wiki also uses this definition here and it even says that:

Quote
When using codomains, the inverse of a function ƒ: X → Y is required to have domain Y and codomain X.

But in question 7, R is "too big" for a codomain. If instead that question had the codomain as [2,6] then it would be fine according to this definition.

It's a better definition in higher mathematics when you're doing more complicated things. But since in vce you are only interesting in sketching graphs etc. I guess we don't need such a definition.
Voltaire: "There is an astonishing imagination even in the science of mathematics ... We repeat, there is far more imagination in the head of Archimedes than in that of Homer."

xZero

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Re: Help please? :) [unit 2]
« Reply #16 on: July 08, 2011, 03:35:37 am »
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hahah i see, didn't know a function can only have an inverse if its a bijection
« Last Edit: July 08, 2011, 03:39:48 am by xZero »
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kamil9876

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Re: Help please? :) [unit 2]
« Reply #17 on: July 08, 2011, 11:56:08 am »
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But as I said before, be careful, judging by the question maybe VCE thinks otherwise.
Voltaire: "There is an astonishing imagination even in the science of mathematics ... We repeat, there is far more imagination in the head of Archimedes than in that of Homer."