Hmmm, yeah well I would concentrate firstly on any

that has modulus signs around it. As long as every

in the expression has modulus signs around it, you know the
graph to the left of the y-axis is a reflection of the graph to the right of the y-axis. If the entire expression has modulus signs around it, then the expression can never be negative.
e.g.
First I would focus on the graph of

(Which is the same as

). As the modulus sign is around the whole expression, you know the graph must never be negative, so every time you get a negative bit, reflect about the x-axis. Then, the minus sign in

simply requires you to flip
everything about the x-axis again.
In

, both the

and the expression have modulus signs around them, so just draw a normal

, but make sure that the graph to the left of the y-axis is a reflection of the graph to the right of the y-axis and never negative.