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March 10, 2026, 11:59:24 am
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Author Topic: Area under curve  (Read 3937 times)  Share 

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dekoyl

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Re: Area under curve
« Reply #15 on: November 05, 2008, 10:02:06 pm »
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Quote from: fredrick on November 05, 2008, 06:51:22 pm

neap
Hey sorry but which year?
I want to have a look myself again before I ask this question myself and waste people's time :P

Thank you.
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fredrick

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Re: Area under curve
« Reply #16 on: November 05, 2008, 10:03:33 pm »
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Quote from: dekoyl on November 05, 2008, 10:02:06 pm
Quote from: fredrick on November 05, 2008, 06:51:22 pm

neap
Neap 08 question 12
Hey sorry but which year?
I want to have a look myself again before I ask this question myself and waste people's time :P

Thank you.
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bec

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Re: Area under curve
« Reply #17 on: November 06, 2008, 08:43:32 am »
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Would someone be able to put that question up? (or even the exam?)
Thanks
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AppleXY

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Re: Area under curve
« Reply #18 on: November 06, 2008, 09:04:05 am »
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How would you find the area of graph?

it would become

But uum how'd you int that hmm

lol
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sxcalexc

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Re: Area under curve
« Reply #19 on: November 06, 2008, 09:09:25 am »
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Would differentiating with respects to the y axis be accepted in the exam?
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cinnamonbun

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Re: Area under curve
« Reply #20 on: November 06, 2008, 09:14:25 am »
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dont think so
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Pandemonium

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Re: Area under curve
« Reply #21 on: November 06, 2008, 11:16:50 am »
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Quote from: AppleXY on November 06, 2008, 09:04:05 am
How would you find the area of graph?

it would become

But uum how'd you int that hmm

lol

y = a^x
ln(y) = ln(a^x)
ln(y) = x.ln(a)
y = e(x.lna)

alternatively, as you were saying, x = loga(y)
then using the log laws, x = lny/lna
x.lna = lny
same thing.
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