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February 22, 2026, 05:22:23 am

Author Topic: Equating gradients  (Read 6578 times)  Share 

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bec

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Equating gradients
« on: November 08, 2008, 04:40:29 pm »
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Does anyone have/can anyone think up any questions that require us to find the value of a point on a graph by equating gradients?
I can't find any examples of it (otherwise I would put one up here so that I actually make sense...)

Thanks

Collin Li

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Re: Equating gradients
« Reply #1 on: November 08, 2008, 05:06:42 pm »
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That's a pretty ambiguous request? Haha. What do you mean?

shinny

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Re: Equating gradients
« Reply #2 on: November 08, 2008, 05:11:32 pm »
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Your request actually fits perfectly into any question that involves finding stationary points =P In those questions, you're just equating gradient to zero and finding those points ahah. For other values, it's the same process so I don't see why you need any specific practise.
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danieltennis

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Re: Equating gradients
« Reply #3 on: November 08, 2008, 05:20:17 pm »
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I think she could be talking about hybrid functions and making the various functions continous with the same gradients?

bec

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Re: Equating gradients
« Reply #4 on: November 08, 2008, 05:37:59 pm »
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haha yeah I know, that was a pretty ambiguous request - I wasn't even totally sure of what I was looking for. I found an example of what i mean though:



Ever seen a question like that?

dekoyl

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Re: Equating gradients
« Reply #5 on: November 08, 2008, 05:40:35 pm »
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Mind posting rest of the question bec? :)

And no I haven't seen one like that so I'd like to attempt it. Thanks.
« Last Edit: November 08, 2008, 05:45:57 pm by dekoyl »

danieltennis

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Re: Equating gradients
« Reply #6 on: November 08, 2008, 05:46:28 pm »
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haha yeah I know, that was a pretty ambiguous request - I wasn't even totally sure of what I was looking for. I found an example of what i mean though:

(Image removed from quote.)

Ever seen a question like that?

This is from one of the VCAA exams. Not to sure what year. Maybe 2003?

onlyfknhuman

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Re: Equating gradients
« Reply #7 on: November 08, 2008, 05:48:14 pm »
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What the gook is that, geesus fug no idea  :-[
« Last Edit: November 08, 2008, 05:59:44 pm by onlyfknhuman »
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bec

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Re: Equating gradients
« Reply #8 on: November 08, 2008, 05:48:30 pm »
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Oh sorry, it got cut off! I'm on a rolllllll tonight...

The question is VCAA 2005 CAS exam 1, Q4

"Show that "

dekoyl

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Re: Equating gradients
« Reply #9 on: November 08, 2008, 05:49:30 pm »
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What the gook is that
Gook. GOOK?


This is from one of the VCAA exams. Not to sure what year. Maybe 2003?

Thank you daniel.

Edit: Ah thanks bec!

Mao

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Re: Equating gradients
« Reply #10 on: November 08, 2008, 07:53:31 pm »
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Oh sorry, it got cut off! I'm on a rolllllll tonight...

The question is VCAA 2005 CAS exam 1, Q4

"Show that "

mmm i see. equating the gradient of AB and BC will yield this relationship.

from my knowledge, they may ask you [though it is very rare] for a composite function that "join smoothly"

if you want to prepare for these, grab a random function [say ] , pick a domain [say ], pick another function type [say ], now try to find values of those variables that makes the graphs join smoothly.

after you've done that a couple times, you'll have pretty good grasp of it.
hope that's what you wanted.
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bec

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Re: Equating gradients
« Reply #11 on: November 08, 2008, 08:07:58 pm »
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Yeah thanks Mao but that's not really what I meant. I don't even know what I meant really, it was (again) just a note I had written to myself a while ago that "equating gradients" was something I had to work on.

So um...disregard this whole thread...? haha

droodles

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Re: Equating gradients
« Reply #12 on: November 08, 2008, 08:13:41 pm »
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dekoyl just derive the word with respect to 'O' and it won't be bad

shinny

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Re: Equating gradients
« Reply #13 on: November 08, 2008, 08:17:01 pm »
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Like that droodles?
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Collin Li

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Re: Equating gradients
« Reply #14 on: November 08, 2008, 08:17:50 pm »
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2GOK