a)
-6^2})

b)

If it applies for first 10m, then domain = [0, 10] (as we are assuming the igloo is above ground level)
Since the graph is basically a parabola which has been squashed by a square root sign, we can find the range by completing the square:
}=\sqrt{-((x-6)^2-36)} = \sqrt{36-(x-6)^2})

the maximum of the

is y = 36 at x = 6 and the maximum of

is y = 6 at x = 6.
To find the minimum, plug in x = 0 and x = 10:


Hence, range is [0, 6]. Sketching the graph and this will be easier to understand (when I do this question I think of the graph shape).
c) Solve

to find the second intercept.
 = 0 \Rightarrow x = 15)
.
Therefore the domain is (10, 15].
Since

is monotonically decreasing, plugging in x = 10 will get you the max, and x = 15 the min.



range =
)
d) Notice that
^2} \Rightarrow y^2 + (x-6)^2 = m^2, \ y \geq 0)
.
i.e. the graph is the top half of a circle of radius 2, centred (6, 0). Hence, m = 2.
e) Take the children to be a rectangle of height 1.6m and width 1.5m.
To find the width allowable at a height of 1.6m, solve
^2})

As the distance

, the children will easily fit through.