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November 01, 2025, 07:35:56 pm

Author Topic: complex numbers  (Read 3530 times)  Share 

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khalil

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complex numbers
« on: December 24, 2008, 10:23:03 pm »
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has any1 seen the binomial method?
ive got the heinemann text book and they have this weird way which involves n's and r's
some1 please explain
solve (3-5i)^5 using the binomial method
thanks

hard

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Re: complex numbers
« Reply #1 on: December 24, 2008, 10:49:14 pm »
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looks pretty simple, just use the binomial method then to simplify and all use the i^2= -1 etc. Not too sure though so correct me anyone?

Mao

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Re: complex numbers
« Reply #2 on: December 25, 2008, 09:23:52 am »
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expand it as any polynomial, but remember

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khalil

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Re: complex numbers
« Reply #3 on: December 25, 2008, 01:35:03 pm »
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yer but it says to use the binomial method

Damo17

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Re: complex numbers
« Reply #4 on: December 25, 2008, 06:23:56 pm »
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yer but it says to use the binomial method

Then use it:


           

Now using that:















If your not sure on your answer straight away when doing question like this, just put it in your calculator with (a+bi) set in mode and you will see if it is right.
« Last Edit: December 25, 2008, 06:28:46 pm by Damo17 »
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Damo17

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Re: complex numbers
« Reply #5 on: December 25, 2008, 07:05:28 pm »
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Khalil: Doesn't the book show the binomial method (like below) and an example?

Binomial Theorem:

           

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khalil

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Re: complex numbers
« Reply #6 on: December 26, 2008, 04:18:48 pm »
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Khalil: Doesn't the book show the binomial method (like below) and an example?

Binomial Theorem:


yer it does but it contains weird things like n over 0

thanks by the way
           



khalil

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Re: complex numbers
« Reply #7 on: December 26, 2008, 04:24:34 pm »
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Can someone do this:
State the values of |z| and Arg z when z equals
-3 cos(- π/3)+ 3i sin (- π/3)

the things that look like n's are pie

ell

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Re: complex numbers
« Reply #8 on: December 26, 2008, 04:47:21 pm »
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Can someone do this:
State the values of |z| and Arg z when z equals
-3 cos(- π/3)+ 3i sin (- π/3)

the things that look like n's are pie


Let





To find , first determine what quadrant the complex number is in. Picture an Argand diagram - since the real part is negative and the imaginary part is also negative it is in the 3rd quadrant.

(since the angle must be in the third quadrant)


khalil

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Re: complex numbers
« Reply #9 on: December 26, 2008, 07:38:59 pm »
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Wow thanks
the method in the book is much more complex

bigtick

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Re: complex numbers
« Reply #10 on: December 26, 2008, 08:29:47 pm »
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-3 cos(- π/3)+ 3i sin (- π/3) = -3 cos(π/3)- 3i sin (π/3) = -3cis(n/3) = 3cis(-2n/3)
|z| = 3, Arg(z) = -2n/3

Damo17

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Re: complex numbers
« Reply #11 on: December 26, 2008, 09:46:55 pm »
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Khalil: Doesn't the book show the binomial method (like below) and an example?

Binomial Theorem:

yer it does but it contains weird things like n over 0

thanks by the way

Yeah, there are different ways of expressing the binomial methods. The one that I did above is Newton's generalized binomial theorem. Below is the one you most likely have is your book.



what is crucial in understanding this is:


To understand better lets use an example. The question I did above.



At this point, to save alot of unnecessary working out, know that and are both equal to 1.












It is rather simple once you understand:
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humph

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Re: complex numbers
« Reply #12 on: December 26, 2008, 09:52:09 pm »
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And of course for small numbers it's much easier to remember the coefficients via Pascal's triangle (though this becomes increasingly impractical for larger numbers).
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Mao

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Re: complex numbers
« Reply #13 on: December 26, 2008, 09:56:04 pm »
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combinatorics are easier to remember like this:



on top, starting with 9, count down 3 numbers, on the bottom, starting with 1, count up 3 numbers



makes life so much easier :)
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khalil

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Re: complex numbers
« Reply #14 on: December 26, 2008, 09:56:36 pm »
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Khalil: Doesn't the book show the binomial method (like below) and an example?

Binomial Theorem:

yer it does but it contains weird things like n over 0

thanks by the way

Yeah, there are different ways of expressing the binomial methods. The one that I did above is Newton's generalized binomial theorem. Below is the one you most likely have is your book.



what is crucial in understanding this is:


To understand better lets use an example. The question I did above.



At this point, to save alot of unnecessary working out, know that and are both equal to 1.












It is rather simple once you understand:

thanks for ur help....i havent done factorials in yr 11 so my understanding of them isnt so great
do u have to use the binomial method a lot ?