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October 10, 2025, 05:59:20 am

Author Topic: TrueTears question thread  (Read 67599 times)  Share 

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TrueTears

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Re: TrueTears question thread
« Reply #255 on: March 06, 2009, 11:07:52 pm »
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ah yes yes yes, thank you so much.
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kamil9876

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Re: TrueTears question thread
« Reply #256 on: March 07, 2009, 12:07:33 am »
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/0 is right, but analytically speaking we havn't ruled out the possibility that there may be more tangents fiting this information. It's probably the only one as the question said to 'use ur diagram' and other heurestical reasoning about the geometry of the situation sort of leads to this conclusion. A way that this may be done analytically, if ur interested, is to first of all find dy/dx (which i assume u hav already done) and then consider the tangent's gradient. The tangent goes through some point on the hyperbola (x,y) and it satisfies the conditions specified by dy/dx. hence u must now find values that satisfy the equation:



You must also make the substituion using the equation of the hyperbola to get rid of either x or y so that only one variable is involved. This is a fuckload of algebra that is beyond what the question was probably designed for, I think some geometrical reasoning can show that indeed x=3 is the only one. Also, the word "the" in "state the equation of the other tangent to the hyperbola" hints that it is the only one.
Voltaire: "There is an astonishing imagination even in the science of mathematics ... We repeat, there is far more imagination in the head of Archimedes than in that of Homer."

TrueTears

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Re: TrueTears question thread
« Reply #257 on: March 07, 2009, 12:20:53 am »
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nice thanks
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TrueTears

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Re: TrueTears question thread
« Reply #258 on: March 07, 2009, 12:38:32 am »
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1. In the triangle OAB, let M, N and P be the midpoint of the sides OB, AB and OA respectively. Let the perpendicular bisectors of sides AB and OA meet at G as shown. Let the position vector of P and M be p and m respectively and let be denoted by r as shown.



a) show that m = p + r

this i have done

b) Let be detnoed by v and be denoted by w, as shown. One possible expression for is = v - p + m = v+r, by a)
Use this expression to show that . p = r . p

how do you do b)?

2. A radar tracking facility tracks a plane flying in a straight line. With the radar facility as the origin, the plane's initial and final position vectors are a = 2i + 8j + k and b = 8i -4j + 13k respectively.
a) Find a unit vector , u , in the direction of the motion of the plane.

this i found to be

b) The position vector of the plane, p, when it is closest to the radar can be expressed as p = a + u, where is a real number. find the value of and hence the plane's position when it is closest to the radar facility.

Any help on b)? I've tried letting p = ai +bj +ck but that just gets too many equations and can't be solved.

thanks guys!
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kamil9876

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Re: TrueTears question thread
« Reply #259 on: March 07, 2009, 12:47:12 am »
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for b, use the distributive properties of the dot product:

GM.p=p.(v+r)
       =p.v + p.r
but p.v=0 as indicated on the diagram(perpendicular to each other)
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kamil9876

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Re: TrueTears question thread
« Reply #260 on: March 07, 2009, 01:18:25 am »
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for the next question, refer to attatched diagram. OA=a, OP=p and OB=b.

OP.AB=0
0=(a+u)(b-a)
0=a.b-a.a+u.b-u.a

because u know a, b, u you can evaluate all those dot products and end up getting some number, with some s in there that you can then work out as they will be the only unkown.
Voltaire: "There is an astonishing imagination even in the science of mathematics ... We repeat, there is far more imagination in the head of Archimedes than in that of Homer."

TrueTears

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Re: TrueTears question thread
« Reply #261 on: March 07, 2009, 11:47:45 am »
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thanks kamil for all your help, I got both of them now XD
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TrueTears

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Re: TrueTears question thread
« Reply #262 on: March 07, 2009, 12:21:24 pm »
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Another question:

Lines y = 2x and y = 10-2x are the asymptotes of a hyperbola of the form.

a) use the equations of the asymptotes to establish a relation between a and b

Just stuck on this part lol
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Mao

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Re: TrueTears question thread
« Reply #263 on: March 07, 2009, 06:12:35 pm »
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the asymptotes are:



from the given gradients of the asymptotes, (q=5, p=2.5)
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TrueTears

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Re: TrueTears question thread
« Reply #264 on: March 07, 2009, 06:13:31 pm »
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oh i see lol, stupid me
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Re: TrueTears question thread
« Reply #265 on: March 07, 2009, 06:25:52 pm »
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another one

Points A, B and C have position vectors andrespectively.

Find AC : BC

i keep getting 5:-3

but can you have a negative ratio? Or is that wrong lols
« Last Edit: March 07, 2009, 06:44:37 pm by Brendan »
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Re: TrueTears question thread
« Reply #266 on: March 07, 2009, 06:49:57 pm »
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AC and BC are scalar quantities, denoting the length of and

so yah, shouldn't be negative.
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Re: TrueTears question thread
« Reply #267 on: March 07, 2009, 06:52:36 pm »
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z.z.z. lol its meant to be the magnitude ratio not their vectors hahahaha
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Re: TrueTears question thread
« Reply #268 on: March 07, 2009, 10:56:50 pm »
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For that big triangle question, how do you do part c
show that GM.m =0
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Re: TrueTears question thread
« Reply #269 on: March 07, 2009, 10:58:35 pm »
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so
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