Please avoid double-posting and instead amend your previous post using the modify button. It would also help to show
some evidence of previous work (working out, what you know about the question, what you have tried). Just some tips for future questions
If you have two points on the xy-plane, you can construct a unique line on the xy-plane. Given the two points \((x_1, y_1)\) and \((x_2, y_2)\) on the line, the line has equation \(y-y_1 = \frac{y_2 - y_1}{x_2-x_1} (x-x_1)\) - (why does this work? that's something for you to consider, this will help you understand more questions in future). Here, we're given the two points \((-4, 3)\) and \((5, -2)\). Construct the line using the directions I've given, and see which points satisfy the equation; the one point that
does satisfy the equation will be the answer.
The y-intercept of a line is calculated by letting \(x = 0\). After you find this point, we must also find the gradient of the line provided. Here, the gradient is \(\frac{3}{2}\) (I didn't pull that number out of thin air; how did I get it? Another question for you to consider). recall that perpendicular lines on the xy-plane have the product of their gradients equalling -1 ie. the equation of the line perpendicular to the line provided will have gradient \(-\frac{2}{3}\). We can construct a unique line given the gradient of a line and a point it passes through. This point is the y-intercept you would have found earlier. Use the point-gradient form of the line from the previous question to find the equation of this particular line.
Hope this helps