Ignore above post: i just found out colour change is between pH ~ 0.15 - 3.2
I don't think temperature change was enough to decrease pH to 0.15. Phosphoric acid is somewhat weak; a 0.01 M solution would have pH = 2.25.
Probs concentration of ur solution was quite low, so pH would be much closer to 3 than it is to 0.15.
We had a solution of 1M and its base pH was approximately 1, so that also rules out that... haha, thank you though
That's not quite right.. I'm fairly sure 1M H3PO4 doesn't get near a pH of 1.
I will do some number crunching later tonight to confirm this.
@Thushan, your interpretation of my post is spot on. But I didn't look up the pKa of the indicator.
Wiki says it does... hahahaha 
Our indicator also suggested it was a pH of 1... green is the mix between blue/violet and yellow, therefore the indicator is in its 'middle'.
I must still be drunk or something. I read 1M as 0.1M. /continuation of herp-a-derp
Seeing as the %ionization argument is a hit-and-miss, I have crunched some thermodynamics data. Here is a very crude estimate of what happens:
1. Equilibrium concentration of the various species at 1M H3PO4 are:

From this, we note that the second and third ionisation are small, and can be neglected.
2. From the enthalpy of formation data,
} \to H_2PO_4^{-}_{(aq)} + H^{+}_{(aq)})
has

(very rough estimate)
3. Applying the Arrhenius equation, the Boltzmann factor
)
increases by a factor of 2.5 as temperature is decreased from 298K to 273K. I.e. Ka1 increases by a factor 2.5. (7.25E-3 M to 1.81E-2 M)
4. Solving for equilibrium concentrations again, we get

(increased by a factor of 1.5),

I don't have the Ka of methyl violet handy, but this crude estimate is something to think about: Is a pH change of ~0.2 noticeable by eye?
This of course depends a lot on the properties of the indicator, at the turning point (indicator ratio HI:I is 1:1), this pH change corresponds to a 20% increase of HI and 20% decrease of I-. The further we deviate from this turning point, the change becomes smaller (i.e. at HI:I of 2:1, this change corresponds to 12% increase of HI). This is probably my best bet on why you couldn't visibly see any change in color.
(This result is somewhat dependent on my estimate of the change in enthalpy. If my estimate is out by a factor of 2 (unlikely, as -50 kJ/mol is a quite strong binding force), the pH change approximately doubles.)