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January 10, 2026, 12:15:49 pm

Author Topic: Solutions  (Read 8207 times)  Share 

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4231

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Solutions
« on: November 08, 2011, 10:48:29 am »
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Anyone wanna put up there answers?
I got 19+3√5 for the max length.
i got a = 8 and m = 4 and
the domain question (-infinity,-8] U [-2,infinity)
thats all i can really remember

nubs

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Re: Solutions
« Reply #1 on: November 08, 2011, 10:52:49 am »
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I'm not sure about the -8 and -2, i think they should both be positive
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Panicmode

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Re: Solutions
« Reply #2 on: November 08, 2011, 10:56:33 am »
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X_x solutions please
« Last Edit: November 08, 2011, 10:58:52 am by Panicmode »
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cltf

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Re: Solutions
« Reply #3 on: November 08, 2011, 10:59:14 am »
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X_x solutions please

[-8,-2]
YESS THATS WHAT I GOT!!!
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Panicmode

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Re: Solutions
« Reply #4 on: November 08, 2011, 11:00:32 am »
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X_x solutions please

YESS THATS WHAT I GOT!!!
Lol you quoted my answer after I changed itcausei realised it was wrong
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4231

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Re: Solutions
« Reply #5 on: November 08, 2011, 11:00:56 am »
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nah they were definitely negative..... here are the solutions http://www.itute.com/board/viewtopic.php?f=2&t=2447&sid=c055dbf10049d49941c3fac0951a56c5

helicopterman1

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Re: Solutions
« Reply #6 on: November 08, 2011, 11:01:10 am »
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I'm pretty sure its not the inner bit ( [-8,-2] ) but the other parts. I just graphed it and used the rule for the subset of domain and the domain is everything but the inner bit?? Is this right?

And its only positive values

cltf

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Re: Solutions
« Reply #7 on: November 08, 2011, 11:02:55 am »
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X_x solutions please

YESS THATS WHAT I GOT!!!
Lol you quoted my answer after I changed itcausei realised it was wrong

Yeh, just graphed it on the cas...another 2 marks gone :(
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tazza

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Re: Solutions
« Reply #8 on: November 08, 2011, 11:04:39 am »
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I got...1a) -1/2(sqrt(4-x))
b) (pi*sqrt(3))/6+(pi^2)/36

2a) 1/3 ln(|3x-4|)+c

b) x = 4

3a) ran  [1,7]
period = 4

b) pi/4, 11pi/12

4)a) c= 8, d = 2
b) dom (-inf, -8]U[-2, inf)

5a) 5/8
b) 3/5

6a) k = -4
b) K = R \{-4,-3}

7a) p^3
b) 3p^2 (1-p)
c) p = 3/4

8a) 3/20
b) 1/4

9) m = 4, a = 8

10) a: a cos(theta), a sin(theta)
B) 4 + 2acos(theta) + asin(theta) + a
c) show that blah blah blah
d) 19 + 3 sqrt(5)
« Last Edit: November 08, 2011, 11:13:17 am by tazza »

4231

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Re: Solutions
« Reply #9 on: November 08, 2011, 11:06:06 am »
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the domain shouldbe -8 and -2 not 8, 2. and i think u put an i where there should be a -

tazza

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Re: Solutions
« Reply #10 on: November 08, 2011, 11:06:52 am »
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the domain shouldbe -8 and -2 not 8, 2. and i think u put an i where there should be a -

Yeah you're right, fixed it.

4231

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Re: Solutions
« Reply #11 on: November 08, 2011, 11:09:47 am »
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and for question 7 b, it should be 1-p not 1ip

tazza

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Re: Solutions
« Reply #12 on: November 08, 2011, 11:13:04 am »
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Do you think it will matter if we write c = 8 d=2; c =2 d = 8; or we write c=8,d=2 OR c=2, d=8 ??? It was too ambiguous

Andiio

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Re: Solutions
« Reply #13 on: November 08, 2011, 11:17:22 am »
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What was Q2(b) asking again?
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BoredSatan

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Re: Solutions
« Reply #14 on: November 08, 2011, 11:18:50 am »
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err.. with the maximal domain.. doesnt it have to be defined for both f(x) and g(x)??

cause between -2 and 3 is not defined for f(x)
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