I know how to do these questions but i dont particularly understand these concepts as the book explanation is very brief and doesnt explain it.
So why is -sin (pie/2 - theta) =a= cos theta
- cos(pie/2 -theta)= b =sin theta
Why is sin (pie/2 + theta)=a =cos theta
Cos (pie/2 +theta) =-b =-sin theta
Pretty sure the first one is wrong. -sin(π/2-θ)=-cos(θ), since sin(π/2-θ) is in the first quadrant and is positive, so the negative of it would be negative.
-cos(π/2-θ)=-sin(θ), similar to first one
sin(π/2+θ) is in the second quadrant which is positive for sine. So sin(π/2+θ)=cos(θ)
cos(π/2+θ) is in the second quadrant, which is negative for cosine, so it's -sin(θ)
This image explains why these identities work if you want to understand it,
Also someone should correct me if I got anything wrong, since I may have made a mistake, which may be why I got a different answer to you.