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September 20, 2025, 10:39:57 pm

Author Topic: VCE Methods Question Thread!  (Read 5689409 times)  Share 

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Ahmad_A_1999

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Re: VCE Methods Question Thread!
« Reply #15045 on: July 07, 2017, 08:16:43 pm »
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Let x1 be the x-coordinate of the left side of the rectangle, and let x2 be the x-coordinate of the right side of the rectangle.

We want to find the length of the rectangle = x2 - x1

We know that the base of the triangle is 6 units (8-2 from the diagram). We also assume that the rectangle is in the centre of the triangle, meaning that there is x1 units between the corner of the triangle and the corner of the rectangle. Since it is in the middle, there is x1 units on both sides = 2x1 units altogether.

Therefore, our length = 6 - 2x1 (does this part make sense? This is the trickiest part of the question :) )

Since our length is in terms of x1, we sub x1 into our linear equation (from part a) to find the corresponding y-value for x1.

Y = 3x1 - 4

We then need to further subtract 2 units, as the rectangle is 2 units above the x-axis, to find the width.

Width = (3x1 - 4) - 2 = 3x1 - 6

Area = length x width
         = (6 - 2x1)(3x1 - 6)

Find the derivate of the area (in terms of x1). Make derivative = 0 to find maximum x1 values. Sub into area equation to find maximum area.

Hope this helps! Let me know if anything doesn't make sense :D

Hey! Thanks for the response!  ;D

I don't get it  :(

I'm confused about finding the length of the rectangle, I'm okay with the other parts though,  :'(
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amigos

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Re: VCE Methods Question Thread!
« Reply #15046 on: July 07, 2017, 08:53:37 pm »
0
Hey peoples - can I please get some help with this question:

When a polynomial P(x) is divided by x-1 and x+2 the remainders are 3 and -9 respectively. Find the remainder when it is divided by (x-1)(x+2).

Thanks!  :)

Edit: Also, can I simplify the following any further?

« Last Edit: July 07, 2017, 09:07:10 pm by amigos »

MisterNeo

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Re: VCE Methods Question Thread!
« Reply #15047 on: July 07, 2017, 09:24:44 pm »
+2

Edit: Also, can I simplify the following any further?



To answer your second question, it can be further simplified.






RuiAce

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Re: VCE Methods Question Thread!
« Reply #15048 on: July 07, 2017, 10:12:11 pm »
+3
Hey peoples - can I please get some help with this question:

When a polynomial P(x) is divided by x-1 and x+2 the remainders are 3 and -9 respectively. Find the remainder when it is divided by (x-1)(x+2).

Thanks!  :)

Edit: Also, can I simplify the following any further?



humblepie

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Re: VCE Methods Question Thread!
« Reply #15049 on: July 08, 2017, 07:14:38 pm »
0
Could someone please explain how to find the range of y=ex2 without using CAS?

Thanks :)
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MisterNeo

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Re: VCE Methods Question Thread!
« Reply #15050 on: July 08, 2017, 07:48:09 pm »
+6
Could someone please explain how to find the range of y=ex2 without using CAS?

Thanks :)

The range of a function is "all possible y-values".
This function has multiple levels of powers so you need to work top-down.
The exponential is to the power of x2. This means that the exponential is to the power of values greater or equal to 0 because you can't get a negative from squaring.


Basically, you have to work top-down the powers to find values of y that can't exist.

TheCommando

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Re: VCE Methods Question Thread!
« Reply #15051 on: July 08, 2017, 11:57:41 pm »
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The range of a function is "all possible y-values".
This function has multiple levels of powers so you need to work top-down.
The exponential is to the power of x2. This means that the exponential is to the power of values greater or equal to 0 because you can't get a negative from squaring.


Basically, you have to work top-down the powers to find values of y that can't exist.
Why is it 1
Why cant it bbe 0

Sine

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Re: VCE Methods Question Thread!
« Reply #15052 on: July 09, 2017, 12:21:47 am »
+4

TFAnime123

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Re: VCE Methods Question Thread!
« Reply #15053 on: July 10, 2017, 01:01:39 pm »
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Can someone help out with this question?

The solution to the equation 4^2x-1 =36 can be written in the form a + log e (b)/log e (4), where a and b are positive integers. Find a and b.
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Jaswinder

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Re: VCE Methods Question Thread!
« Reply #15054 on: July 10, 2017, 01:29:20 pm »
+4
\[4^2^x^-^1=36\]

\[\log_{e}36/\log_{e}4=2x-1\]

\[\frac{1}{2}(\log_{e}36/\log_{e}4 +1) =x\]

\[(\log_{e}6/\log_{e}4 +0.5) =x\]




humblepie

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Re: VCE Methods Question Thread!
« Reply #15055 on: July 10, 2017, 08:33:03 pm »
+1
Would really appreciate some help with this question:

Solve for x: -n/xn+1 > -(n+1)/xn+2

The answer is 0<x< (n+1)/n (I don't understand why x has to be greater than 0)

Thanks in advance! :)
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scout

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Re: VCE Methods Question Thread!
« Reply #15056 on: July 11, 2017, 11:06:18 am »
+1
Would really appreciate some help with this question:

Solve for x: -n/xn+1 > -(n+1)/xn+2

The answer is 0<x< (n+1)/n (I don't understand why x has to be greater than 0)

Thanks in advance! :)

Hmm I agree... why can't x also be LESS than zero (just not equal to zero)? 

Syndicate

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Re: VCE Methods Question Thread!
« Reply #15057 on: July 11, 2017, 08:35:47 pm »
+1
Would really appreciate some help with this question:

Solve for x: -n/xn+1 > -(n+1)/xn+2

The answer is 0<x< (n+1)/n (I don't understand why x has to be greater than 0)

Thanks in advance! :)

Think about it graphically by letting n be equal to any integer (except -1, 0 or -2 of course).

(use desmos if you want)
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scout

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Re: VCE Methods Question Thread!
« Reply #15058 on: July 11, 2017, 08:53:51 pm »
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Think about it graphically by letting n be equal to any integer (except -1, 0 or -2 of course).

(use desmos if you want)

I suppose it can't be shown algebraically (without trial and error) ?

Lavar Big BBB Balls

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Re: VCE Methods Question Thread!
« Reply #15059 on: July 12, 2017, 02:15:26 pm »
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Hi

For this http://imgur.com/a/Bl2Ew

I don't understand how 9dii and iii can have a different answer? ii is dependent and iii is independent but what they're both saying is "given the sum of the 2 numbers is at least "x", what is the probability of A occurring?".

If we know C or D occurs then wouldn't this affect the probability of A occurring? this makes me believe that they are both dependent.

note: I know that for iii Pr(A|D) = Pr(A) which means it's independent but it doesn't seem very intuitive otherwise.

Thanks
« Last Edit: July 12, 2017, 03:24:22 pm by Lavar Big BBB Balls »