Hey everyone
I need help with a binomial distribution question.
Rex is shooting at a target. His probability of hitting the target is 0.6. What is the minimum number of shots needed for the probability of Rex hitting the target exactly five times to be more than 25%?
Pls help. 
For the Casio ClasspadWe know:
pr(success)=.6
number of successes=5
let number of trials=x
In your main, you can enter this as:
binomialPDf(5,x,.6)
However, we are not trying to solve for anything in main.
Instead, we are going to highlight it all and copy/cut it.
Enter graph&tables.
For your 'y1', paste the 'binomialPDf(5,x,.6)' from before and tick the box.
Instead of pushing the usual graph icon, press the button on the right of it to enter your table.
Your x values will represent the number of trials.
Your y1 values represents the corresponding probability.
In this context, when 'x' number of trials have occurred, your y1 value represents the probability of 'Rex hitting the target exactly five times'.
...
at x=5 y1=.0778
at x=6 y1=.1866
at x =7 y1=.2613at x=8 y1=.2787
...
When your y1 first exceeds .25, it provides your lowest number of trials, x.
Thus minimum number of trials being x is 7, satisfying the condition that the probability exceeds .25.
Feel free to adjust your starting/ending x values & the size of the steps between your x values.
Once you are in your table, you can easily adjust these values through pushing the icon that lies most right (has x and y in it with arrows pointing up and left).
Hope that helped mate.
Have a great night!
