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November 08, 2025, 02:26:05 pm

Author Topic: VCE Methods Question Thread!  (Read 5782874 times)  Share 

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Kayte

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Re: VCE Methods Question Thread!
« Reply #2895 on: October 27, 2013, 10:45:56 pm »
0
Could somebody explain to me do Question 4C in the 2011 Exam 2.
I've been looking at the VCAA solutions for a while and I don't really understand why they're taking those steps.

Thanks!!

b^3

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Re: VCE Methods Question Thread!
« Reply #2896 on: October 27, 2013, 11:02:38 pm »
+4
You need to add up the time taken for him to run on land and the time taken for him to swim up the river.
If he runs at 2 km/h, then the time taken will be give by , so . So we need the total distance that he runs, and then divide it by his speed. Since he is running from his camp at to a point on the river , which since we know it is on that curve is , we can use the distance formula, , or you can just look at it using pythagoras. Anyways that gives:


Now for the time it take him to swim. We are told that this time is 'proportional to the difference between the coordinates of the desalination plant (which is ) and the point where he enters the river (which is ).
So since it is 'proportional to', we have to introduce the constant of proportionality . If something is proportional to something else, then as the first changes the second will change by a scalar amount according to how it is proportional to the first. i.e. If is directly proportional to , that is , then , where . If say for example we had is proportional to the square of the coordinate, we would have , so changes a certain amount for each change in .

The difference between the coordinates is


As is proportional to this we have, .
Now the sum of those two gives us the total time taken, hence
« Last Edit: October 28, 2013, 12:14:07 pm by b^3 »
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Kayte

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Re: VCE Methods Question Thread!
« Reply #2897 on: October 28, 2013, 01:08:42 am »
0
You need to add up the time taken for him to run on land and the time taken for him to swim up the river.
If he runs at 2 km/h, then the time taken will be give by , so . So we need the total distance that he runs, and then divide it by his speed. Since he is running from his camp at to a point on the river , which since we know it is on that curve is , we can use the distance formula, , or you can just look at it using pythagoras. Anyways that gives:


Now for the time it take him to swim. We are told that this time is 'proportional to the difference between the coordinates of the desalination plant (which is ) and the point where he enters the river (which is ).
So since it is 'proportional to', we have to introduce the constant of proportionality . If something is proportional to something else, then as the first changes the second will change by a scalar amount according to how it is proportional to the first. i.e. If is directly proportional to , that is , then , where . If say for example we had is proportional to the square of the coordinate, we would have , so changes a certain amount for each change in .

The difference between the coordinates is


As is proportional to this we have, .
Now the sum of those two gives us the total time taken, hence


Thanks so much!  :D

clıppy

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Re: VCE Methods Question Thread!
« Reply #2898 on: October 28, 2013, 08:33:51 pm »
0
These questions from IARTV 2012 absolutely stumped me.

a) If         find f(-2)
b) If the domain of f(x) is restricted to (-ve infinity, -1], what is the restricted domain of

See attached photo:
a) Show that
b) Find the ratio of r to a such that the volume of the cone is minimal

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Re: VCE Methods Question Thread!
« Reply #2899 on: October 28, 2013, 08:45:19 pm »
+1
let u = 3/x+2

f(u) = (x+3)^2

solve for x in terms of u

for b, think about the relationship between u and x... if x is restricted, how does that influence u?
« Last Edit: October 28, 2013, 08:47:45 pm by TrueTears »
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lzxnl

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Re: VCE Methods Question Thread!
« Reply #2900 on: October 28, 2013, 09:07:34 pm »
+1
These questions from IARTV 2012 absolutely stumped me.

a) If         find f(-2)
b) If the domain of f(x) is restricted to (-ve infinity, -1], what is the restricted domain of

See attached photo:
a) Show that
b) Find the ratio of r to a such that the volume of the cone is minimal

In the diagram, consider the triangle with perpendicular side lengths h-2a and a. That triangle is similar to the large triangle with perpendicular side lengths h and r. Thus we can write (h-2a)/a=h/r
h/a - 2=h/r
h/a-h/r=2
h(r-a)/ar=2
h=2ar/(r-a)

Now your volume is some constant times r^2h (yes the constant is pi/3; that's not needed here though).
r^2h=2ar^3/(r-a)
which is some constant times r^3/(r-a)

OK, so we differentiate this and set to zero.
(3r^2(r-a)-r^3)/(r-a)^2=0
we don't want r=0
3(r-a)=r
3r=r+3a
r=3a/2
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darklight

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Re: VCE Methods Question Thread!
« Reply #2901 on: October 28, 2013, 09:15:01 pm »
0


See attached photo:
a) Show that
b) Find the ratio of r to a such that the volume of the cone is minimal


A really similar question (part a) was tested in 2010 VCAA Exam 1 if you wanted to check it out :)
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shadows

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Re: VCE Methods Question Thread!
« Reply #2902 on: October 28, 2013, 10:15:51 pm »
0
VCAA Exam 2 08
Section 1
Q15.

The sample space when a fair die is rolled is {1,2,3,4,5,6} with each outcome being equally likely. Which of the following pairs of events are the events independent?

I've looked at the solutions but I still don't get it

Its {1,2} and {2,4,6}

Someone care to explain?


EDIT FIXED sorry yeah its E, not D
« Last Edit: October 28, 2013, 10:32:00 pm by shadows »

ahat

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Re: VCE Methods Question Thread!
« Reply #2903 on: October 28, 2013, 10:28:35 pm »
+2
VCAA Exam 2 08
Section 1
Q15.

The sample space when a fair die is rolled is {1,2,3,4,5,6} with each outcome being equally likely. Which of the following pairs of events are the events independent?

I've looked at the solutions but I still don't get it

Its {1,2} and {1,3,4,6}
 
Someone care to explain?


For independance, Pr(A n B) = Pr(A) x Pr(B)

If we had this option:
{1,2} and {1,3,4,6}

And let A = {1,2} and B = {1,3,4,6}
Then Pr(A) = 2/6. That means, two possibilities out of the total subset of 6
Then, Pr(B) = 4/6
Hence, for these to be defined as 'independant events' then Pr(A n B) = 2/6 x 4/6 = 2/9
Okay, I can already see there's a mistake. I went to the solutions and the answer is E, not D .
(btw, we know this is wrong, the intersection we calculated implies the subset has 9 numbers)

So, Let A = {1,2} and Let B = {2,4,6}
Pr(A) = 2/6 and Pr(B) = 3/6
Pr(A n B) should = 2/6 x 3/6 = 1/6
Pr(A n B) actually = 1/6
So true
How do we calculate Pr(A n B)? We see that  2 is the same in each case. Therefore, one number out of a total subset of 6. So 1/6

*look at what you guys are doing to me. I was trying to do English :P *
« Last Edit: October 28, 2013, 10:37:56 pm by ahat »
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b^3

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Re: VCE Methods Question Thread!
« Reply #2904 on: October 28, 2013, 10:30:21 pm »
+1
You may have looked at the wrong column in the assessors report :P
The last column is the % that didn't answer the quesiton, while the second last column is E not D, so the answer is E.


Two events are independent if on has not effect on the outcome of the other and vice versa, which results in and . Then looking a the conditional probability formula this implies
(we replace the part in the original formula with .
So for the above we'll let event be that we roll a 1 or a 2, and event be that we roll a 2,4 or 6.


(only outcome common to both is 1)

Hence the events are independent :)

EDIT: Beaten
« Last Edit: October 28, 2013, 10:33:52 pm by b^3 »
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shadows

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Re: VCE Methods Question Thread!
« Reply #2905 on: October 28, 2013, 10:40:15 pm »
0
Thanks! Was this like the question that top students got wrong or something?
It says no one got full marks for this exam. I reckon the 08 paper was comparable to the 06 in terms of difficulty. Surprised to see the cutoff be much lower than the 06 one.

Also, (same exam VCAA 08 Q3a)

I put 3 hours 11 minutes

Answer says 192 mins (3hours 12 mins). But at that time concentration is already 100, wouldn't he already be dead?

Will i still get the answer mark. I did justify at 3 hours 12 mins he would be dead....

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Re: VCE Methods Question Thread!
« Reply #2906 on: October 28, 2013, 11:24:31 pm »
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i understand where you're coming from but to answer your question, no you would not get the answer mark as your final answer is not what they have on their marking scheme. Also it says "to the nearest minute" signalling you should round to the closest integer.
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Re: VCE Methods Question Thread!
« Reply #2907 on: October 29, 2013, 10:00:42 am »
0
My calculator is giving general solutions for this sorta question when I use the "Solve" function. Is it supposed to do that or is it because my calc settings have stuffed up?
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Re: VCE Methods Question Thread!
« Reply #2908 on: October 29, 2013, 10:15:29 am »
0
Thanks for your reply ! :)

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Re: VCE Methods Question Thread!
« Reply #2909 on: October 29, 2013, 10:19:28 am »
+2
Thanks for your reply ! :)

TI - Nspire CAS with the touchpad! :)

After you close the brackets on the solve function, add:



That's saying, solve this for x, given that x is between these two values; the CAS won't give a general solution now.

The line can be found with all the inequalities, CTRL -> EQUALS.
« Last Edit: October 29, 2013, 10:21:50 am by Zealous »
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