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June 04, 2024, 03:33:36 pm

Author Topic: VCE Methods Question Thread!  (Read 4877602 times)  Share 

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Tasmania Jones

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Re: VCE Methods Question Thread!
« Reply #6060 on: September 26, 2014, 11:13:28 pm »
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Hey guys,
When a question asks for the domain over which a function is STRICTLY decreasing/increasing, does it include stationary points or endpoints?
Cheers
Tasmania Jones
2014: Mathematical Methods CAS | Chinese SL

knightrider

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Re: VCE Methods Question Thread!
« Reply #6061 on: September 26, 2014, 11:14:57 pm »
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[/quote]
You could do it through addition of ordinates I guess, or you can just split it up into its hybrid equations and graph those. Yeah it's definitely within the course.



Thanks

kinslayer

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Re: VCE Methods Question Thread!
« Reply #6062 on: September 26, 2014, 11:15:14 pm »
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How would you graph this question and is it possible that this question can be tested in maths methods


The best way is to graph both equations and then just add the y-coordinates together. You could split up the domains but it's quicker just to get to drawing.

kinslayer

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Re: VCE Methods Question Thread!
« Reply #6063 on: September 26, 2014, 11:30:02 pm »
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Hey guys,
When a question asks for the domain over which a function is STRICTLY decreasing/increasing, does it include stationary points or endpoints?
Cheers
Tasmania Jones

It can include stationary points. For example, f(x) = x^3 is strictly increasing for all real x, yet its first and second derivatives are equal to zero at x = 0.

The endpoints of a domain are usually not very interesting when considering monotonicity (increasing/decreasing) since monotonicity is concerned with intervals rather than points. A point isn't an interval so it does not make sense to talk about whether a function is "monotonic" there.

Put it this way: if a continuous function is strictly increasing/decreasing on some open interval I, then it is also strictly increasing/decreasing (respectively) on the closed interval made up of I together with its endpoints.
« Last Edit: September 26, 2014, 11:36:25 pm by kinslayer »

knightrider

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Re: VCE Methods Question Thread!
« Reply #6064 on: September 27, 2014, 07:00:37 pm »
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How would you complete the square on the following equation?


psyxwar

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Re: VCE Methods Question Thread!
« Reply #6065 on: September 27, 2014, 07:23:57 pm »
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How would you complete the square on the following equation?


Take out a as a common factor then complete the square as usual. If you're interested you can also derive the quadratic formula doing this
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knightrider

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Re: VCE Methods Question Thread!
« Reply #6066 on: September 27, 2014, 08:41:42 pm »
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Take out a as a common factor then complete the square as usual. If you're interested you can also derive the quadratic formula doing this
Could you show me how to do this

For maths methods are you expected to know how to graph circles because in the year 12 books they dont cover this?

Bronzebottom64

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Re: VCE Methods Question Thread!
« Reply #6067 on: September 27, 2014, 09:11:10 pm »
+1
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Tasmania Jones

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Re: VCE Methods Question Thread!
« Reply #6068 on: September 27, 2014, 10:13:52 pm »
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It can include stationary points. For example, f(x) = x^3 is strictly increasing for all real x, yet its first and second derivatives are equal to zero at x = 0.

The endpoints of a domain are usually not very interesting when considering monotonicity (increasing/decreasing) since monotonicity is concerned with intervals rather than points. A point isn't an interval so it does not make sense to talk about whether a function is "monotonic" there.

Put it this way: if a continuous function is strictly increasing/decreasing on some open interval I, then it is also strictly increasing/decreasing (respectively) on the closed interval made up of I together with its endpoints.


Thanks kinslayer  :)
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knightrider

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Re: VCE Methods Question Thread!
« Reply #6069 on: September 27, 2014, 11:56:09 pm »
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For maths methods 3/4 are you expected to know how to graph circles because in the year 12 books they dont cover this?

psyxwar

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Re: VCE Methods Question Thread!
« Reply #6070 on: September 27, 2014, 11:58:20 pm »
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For maths methods 3/4 are you expected to know how to graph circles because in the year 12 books they dont cover this?
uhh I guess? not sure, they're not particularly hard to graph though

(x-h)^2+(y-k)^2=r^2, r is radius, (h,k) is centre
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knightrider

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Re: VCE Methods Question Thread!
« Reply #6071 on: September 28, 2014, 12:01:21 am »
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uhh I guess? not sure, they're not particularly hard to graph though

(x-h)^2+(y-k)^2=r^2, r is radius, (h,k) is centre

thanks and also can anyone tell if they have ever got a question about circles in a year 12 sac

Mieow

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Re: VCE Methods Question Thread!
« Reply #6072 on: September 28, 2014, 12:07:43 am »
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the answer is h= (10-5r)/2
but why isn't it h=5r/2?
« Last Edit: September 28, 2014, 12:09:34 am by Mieow »
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IndefatigableLover

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Re: VCE Methods Question Thread!
« Reply #6073 on: September 28, 2014, 12:15:59 am »
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(Image removed from quote.)

the answer is h= (10-5r)/2
but why isn't it h=5r/2?
Well if you aligned up your way of similar triangles, you'll see that the 'base' of the triangle (that is the 'r' side) isn't 'r' but 2-r. 'r' is the radius of the cylinder but not the radius of the cone (which is what 2cm). If you took this value then your value for 'h' would have to change since your 'similar triangle' would be wrong (it's not aligned up and wouldn't be a triangle in the end).

To make sense of what I'm saying, in your diagram, draw the triangle you see where the bottom right corner of the cylinder makes with the cone and draw that triangle out and label the sides you make to get that triangle. That's what you need to find which reflects the correct answer.

bobisnotmyname

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Re: VCE Methods Question Thread!
« Reply #6074 on: October 03, 2014, 11:44:39 am »
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hey guys :)
i'm having a bit of trouble with the general solutions, so any general tips would be great :D
I tried this question sin(2x)=1

i got the initial solution as pi/2                   2x=pi*n+(-1)^n *pi/2
and finally x=(pi*n)/2 +(-1)^n *pi/4
however the correct solution was x=n*pi + pi/4
it was a multiple choice question in the Essentials math methods book