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August 24, 2025, 06:27:38 pm

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2580628 times)  Share 

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brightsky

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Re: Specialist 3/4 Question Thread!
« Reply #1335 on: February 23, 2013, 11:07:43 pm »
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oh soz i see what your problem is now; 'tis a dodgy question, because for all real coefficients, the complex roots need to be conjugates of one another.
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ashs_vb

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Re: Specialist 3/4 Question Thread!
« Reply #1336 on: February 24, 2013, 02:38:52 pm »
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if cos^2(x) + sin^2(x)=1
then   cos^2(x) + sin^2(x)= 1.(cos^2(x) + sin^2(x))
                                          = {cos^2(x) + sin^2(x)}.{cos^2(x) + sin^2(x)}
hence cos^2(x) + sin^2(x)= {cos^2(x) + sin^2(x)}^n    N is an element of R

Is this correct?
Just wondering

Jayward

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Re: Specialist 3/4 Question Thread!
« Reply #1337 on: February 24, 2013, 03:43:21 pm »
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if cos^2(x) + sin^2(x)=1
then   cos^2(x) + sin^2(x)= 1.(cos^2(x) + sin^2(x))
                                          = {cos^2(x) + sin^2(x)}.{cos^2(x) + sin^2(x)}
hence cos^2(x) + sin^2(x)= {cos^2(x) + sin^2(x)}^n    N is an element of R

Is this correct?
Just wondering

Yeap :D

What about this? I know this is pretty dumb, but am having a serious mental blank. Im pretty sure that Im right, but i just wanted to make sure

Conic

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Re: Specialist 3/4 Question Thread!
« Reply #1338 on: February 24, 2013, 03:49:47 pm »
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Yeap :D

What about this? I know this is pretty dumb, but am having a serious mental blank. Im pretty sure that Im right, but i just wanted to make sure
Its , since

A little more info:

Let

then

Now from pythagoras' theorem:



« Last Edit: February 28, 2013, 10:34:21 pm by Conic »
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Jayward

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Re: Specialist 3/4 Question Thread!
« Reply #1339 on: February 24, 2013, 03:52:27 pm »
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Its , since

thanks! serious mental blankness! I shouldve remembered that you take out i when you determine the modulus! :D hahahah

jono88

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Re: Specialist 3/4 Question Thread!
« Reply #1340 on: February 24, 2013, 06:37:03 pm »
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If z=2icis(θ)-1/2icis(- θ)
Show that z lies on the ellipse with equation y^2/25 + x^2/9=1/4

I solved everything into x and y components, simplified and got x^2/25 + y^2/9=1/4 instead. :/

Hancock

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Re: Specialist 3/4 Question Thread!
« Reply #1341 on: February 24, 2013, 06:51:36 pm »
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If z=2icis(θ)-1/2icis(- θ)
Show that z lies on the ellipse with equation y^2/25 + x^2/9=1/4

I solved everything into x and y components, simplified and got x^2/25 + y^2/9=1/4 instead. :/


























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jono88

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Re: Specialist 3/4 Question Thread!
« Reply #1342 on: February 24, 2013, 07:14:38 pm »
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^YES I GOT THE EXACT SAME THING

jono88

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Re: Specialist 3/4 Question Thread!
« Reply #1343 on: February 24, 2013, 08:31:00 pm »
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well w=2i cis(theta) and z=w- w^-1

unless z = 2i*cis*\theta - \frac{1}{2i}*cis(-\theta) ?

Hancock

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Re: Specialist 3/4 Question Thread!
« Reply #1344 on: February 24, 2013, 08:33:13 pm »
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well w=2i cis(theta) and z=w- w^-1

unless z = 2i*cis*\theta - \frac{1}{2i}*cis(-\theta) ?

I read your question as

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jono88

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Re: Specialist 3/4 Question Thread!
« Reply #1345 on: February 24, 2013, 08:35:39 pm »
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z=w-(1/w)


Will T

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Re: Specialist 3/4 Question Thread!
« Reply #1346 on: February 25, 2013, 07:12:28 pm »
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Question 3b. Essentials Exercise 2D. Help please.
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Nobby

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Re: Specialist 3/4 Question Thread!
« Reply #1347 on: February 25, 2013, 07:23:58 pm »
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Question 3b. Essentials Exercise 2D. Help please.

Find the unit vector of the vector that bisects the line from A to B.

saba.ay

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Re: Specialist 3/4 Question Thread!
« Reply #1348 on: February 25, 2013, 07:42:31 pm »
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Can someone pleasedo question 2b maths quest chapter 1 review extended response. I need the working out. I get y=2x + 4/(x(1-x) but the answer is y=2x + 4/(x(1-4)).

??

Please and thanks

Jayward

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Re: Specialist 3/4 Question Thread!
« Reply #1349 on: February 25, 2013, 07:57:28 pm »
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What would this graph look like? I have no clue. I vaguely think its a circle, but am not entirely sure