Yawho - I'm sure you don't mean it, but you're coming across as a tad aggressive - so just watch your tone

Anyways, to answer that inclined plane question:
The 1 kg object on the inclined plane is AT REST. This means that the resultant force on the object is 0 N, via F = ma (Newton's 2nd Law).
There is the gravitational force from the Earth ON the object of 10 N going vertically down.
There is the frictional force on the object going up the plane.
There is the NORMAL reaction force on the object going perpendicular to the direction of the plane. Btw - normal = perpendicular.
What your teacher might have meant is that the frictional force is a reaction force of the plane on the block in a way because friction arises from the rubbing of two rough surfaces where part of the object gets 'caught' within a microscopic cavity of the plane and pushes at it, and the plane pushes back up the object (reaction force) - and that constitutes friction. So the total reaction force is the sum of the normal reaction force + the frictional force (which one can argue is a reaction force too) = 10 N upwards - because the sum of those two forces must be equal and opposite to the gravitational force downwards (10 N) as the resultant force on object is 0 N.