We know the graph passes through the origin (0,0) and the points (2,0)/(-2,0)
We can set up a simultaneous equation to find the equation of the parabolas. Let's tackle the right parabola first

Substitute in one set of coordinates
^{2} +2b +c)
)
Substitute in the other set of points
^{2}+0+c)
)
Substitute (2) into (1) and the formula of the right parabola reveals itself to be:

Repeat the same process for the other parabola, or use your tranformation skillz. The equation of the left parabola should be

Now, the height of the parabola will be the y coordinate of that point. I don't think you've covered calculus yet, so convert the formulas of the parabolas into
turning point form (sorry, I've forgotten how to do it! I'm sure you can do it

) and you can read the turning point from there. You should get (1,2) for the turning point, so the height is 2 units.
We want to restrict these parabolas, so that they run from (0,0) to (2,0) and (-2,0), and not continue on forever.
The domain of the
right parabola would be [0,2] and the domain of the
left parabola would be [-2,0]For the 'W' parabola, same thing. Try it yourself. You are given, for each parabola, two sets of coordinates: the one with the 3 in it, and the y-intercept, which we know to be (0,9)