Derivatives of Log... Help

[GoodGuys]

Hi guys,

My brain isnt getting around why ^2log Square root(x) becomes ^(1/x).

I know how they got the 1 though ain't the x supposed to be square root(x)

just that square root is pissing me off

[TrueTears]

what do you mean by ^2log square root(x) ?

do you mean base 2 log or..?

[GoodGuys]

ummm. how can i explain...
if i knew how to write the equation on the pc it would of helped more...

2 LOG (squareroot(x)) .... does this help?

[TrueTears]

What base is the log? base e?

[GoodGuys]

yep log(e)

[TrueTears]

Remember the derivative of is

[GoodGuys]

thanks.

[Damo17]

or you could just simplify it to:



so

simplifying here makes it easier as you don't have to use chain rule.

[Mao]

or you could just simplify it to:



so

simplifying here makes it easier as you don't have to use chain rule.

A good method, but remember algebra cannot change the domain.

so the final step should be written as

[same goes for TT]

[edited, acknowledgments to FA]

[Flaming_Arrow]

or you could just simplify it to:



so

simplifying here makes it easier as you don't have to use chain rule.

A good method, but remember algebra cannot change the domain.

so the final step should be written as

[same goes for TT]

shouldnt it be ?

[TrueTears]

or you could just simplify it to:



so

simplifying here makes it easier as you don't have to use chain rule.

A good method, but remember algebra cannot change the domain.

so the final step should be written as

[same goes for TT]

shouldnt it be ?

Yeah, I think it should because you can not have 0 for a log

[Mao]

oooops