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October 21, 2025, 05:04:52 am

Author Topic: Matrices HELP!!!  (Read 1441 times)  Share 

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astone788

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Matrices HELP!!!
« on: October 28, 2012, 03:37:55 pm »
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Need help with this question

NOTE: the answer is 3. (option 2,3 and 5)
I understand option 2 and 3 have a unique solution because they have a determinant that is NOT zero. But i don't understand why option 5 has a unique solution.
MY prediction is that option 5 has a assumed determinant of 1. Can anyone clarify this?

StumbleBum

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Re: Matrices HELP!!!
« Reply #1 on: October 28, 2012, 03:43:20 pm »
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Option five has a determinant of 1.

| 1 0 |
| 0 1 |

So the determinant is (1 x 1 - 0 x 0) which equals (1)

Hence it also has a unique solution, along with options 2 and 3.
« Last Edit: October 28, 2012, 03:44:56 pm by StumbleBum »
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astone788

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Re: Matrices HELP!!!
« Reply #2 on: October 28, 2012, 03:44:20 pm »
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Option five has a determinant of 1.

| 1 0 |
| 0 1 |
Where did you get those figures from?

StumbleBum

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Re: Matrices HELP!!!
« Reply #3 on: October 28, 2012, 03:47:52 pm »
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The equation would be represented in matrix form by:

| 1 0 | x | x | = | 8 |
| 0 1 |    | y |    | 2 |

So the first matrix | 1 0 | will be what determines the solutions, as it is what we have to take the inverse of. So as it's determinant is 1 there
                           | 0 1 |
will be a unique solution.
                           
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rife168

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Re: Matrices HELP!!!
« Reply #4 on: October 28, 2012, 03:50:29 pm »
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If you were to set up option 5 as a matrix equation you would get the identity matrix as the coefficient matrix which has a determinant of 1.

For all the options, just find the determinant of the coefficient matrices, if they are non-zero then there is a unique solution.
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astone788

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Re: Matrices HELP!!!
« Reply #5 on: October 28, 2012, 03:52:11 pm »
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ok. thanks for your help!

rife168

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Re: Matrices HELP!!!
« Reply #6 on: October 28, 2012, 03:54:11 pm »
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If you think about it, option 5 should be the most obvious of the choices. Think about what constitutes a unique solution, you have a single value for both x and y. In the case of option 5, you don't even need to do any working out, they simply give you the single values for x and y!
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julie9300

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Re: Matrices HELP!!!
« Reply #7 on: October 30, 2012, 11:34:28 am »
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I think using matrices would be wasting a bit a time to find whether or not there's a unique solution. A unique solution pretty much means that two linear functions intersect with one another and so for that to happen, the two functions cannot have the same gradient. x=8 has an undefined gradient and y=2 has a gradient of 0. Even without looking at the gradients, you can tell that those two lines will intersect at (8,2) and since they intersect they therefore have a unique solution.
« Last Edit: October 30, 2012, 02:53:55 pm by julie9300 »
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Yendall

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Re: Matrices HELP!!!
« Reply #8 on: October 30, 2012, 12:16:06 pm »
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It doesn't take long to work out determinants on your calculator though.











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