My Solutions (Core; Graphs; Networks; Matrices)

[Varunchka]

Not too sure but... Is Graphs + Rel Q.7 E?

I'm fairly sure it is A. How did you get E?
The gradient of the line is 5/2. So k in y = k/x should equal 5/2.
So shouldn't it be y = 5/2x?

AHHHHHH!! I SEE!!! That is such an amateur assumption! Damn!! 39/40

Hmm... That's interesting. But the point (2,5)doesn't lie on the line y=5/2x, does it??

Poop. I was really hoping for 40/40.

It doesn't but the x-value 2 is the value after the transformations have taken place.

[Yendall]

ALSO, i had all the same matrices. So they should be right.

I can confirm this as well, those answers are correct

[oneoneoneone]

Isnt Q5 Networks D?

[sg]

I also have networks Q5 D and Q9 is C, anyone else get C for Q9?

[Tonychet2]

Isnt Q5 Networks D?

yes it should be

[Yendall]

Isnt Q5 Networks D?

yes it should be

How is it D? minimum completion time is 18, so you only need to reduce 2 hours, thus 2 activities?
wrong question hahaahah

[Yendall]

I OBJECT:

Question 8 in Networks:

If you forward and backward scan this network, the minimum completion time is 18 | 18. It says the duration of each activity can be reduced by one hour.
To complete this project in 16 hours, the minimum number of activities that must be reduced by one hour each is:

If the completion time is 18, you need to reduce it by 2 hours. If you reduce 2 activities by one hour each (as that's the limit) shouldn't the answer be B?

This is given that I've forward scanned and backward scanned correctly, which I believe I have. If I haven't, please subject me to the highest form of shame.

[Will T]

I have completed solutions for Number patterns, I found it incredibly easy and am regretting not doing it on the exam.
We now have rough solutions for all the Modules and Core, so hopefully if we can have some debate we will have a correct set of solutions between us.

[pwntnubs]

I think there are 2 critical paths so if you reduce F and H then you gotta reduce E as well

[oppalovesme]

I OBJECT:

Question 8 in Networks:

If you forward and backward scan this network, the minimum completion time is 18 | 18. It says the duration of each activity can be reduced by one hour.
To complete this project in 16 hours, the minimum number of activities that must be reduced by one hour each is:

If the completion time is 18, you need to reduce it by 2 hours. If you reduce 2 activities by one hour each (as that's the limit) shouldn't the answer be B?

This is given that I've forward scanned and backward scanned correctly, which I believe I have. If I haven't, please subject me to the highest form of shame.

Sorry, but it should be C.
There are two critical paths : A-F-H and B-C-F-H (18 hours each), as well as the path A-E-G (17 hours).
To reduce the critical paths to 16, H must be reduced, and reducing A and B then brings all the paths over 16 hours down to 16 hours. (hard to explain sorry!)

[bro0012]

Can anyone explain how to do Q11 in core?

[biancajames]

I also have networks Q5 D and Q9 is C, anyone else get C for Q9?

i also got c !

[Yendall]

I OBJECT:

Question 8 in Networks:

If you forward and backward scan this network, the minimum completion time is 18 | 18. It says the duration of each activity can be reduced by one hour.
To complete this project in 16 hours, the minimum number of activities that must be reduced by one hour each is:

If the completion time is 18, you need to reduce it by 2 hours. If you reduce 2 activities by one hour each (as that's the limit) shouldn't the answer be B?

This is given that I've forward scanned and backward scanned correctly, which I believe I have. If I haven't, please subject me to the highest form of shame.

Sorry, but it should be C.
There are two critical paths : A-F-H and B-C-F-H (18 hours each), as well as the path A-E-G (17 hours).
To reduce the critical paths to 16, H must be reduced, and reducing A and B then brings all the paths over 16 hours down to 16 hours. (hard to explain sorry!)

dang haha

[oppalovesme]

Can anyone explain how to do Q11 in core?

Add all the long-term average rainfalls together (=216.6), then divide by 4. This gives the seasonal average. Then, dividing the average for spring (61.3) by the seasonal average gives the seasonal index, roughly equal to 1.13.

[Yendall]

For question 5 of networks.

For a complete graph to have an Euler Circuit the vertices must all be of even degree when transformed to planar. [I wasn't meant to say that, Planar is irrelevant]

Network 1 has 4 vertices of odd degree
Network 2 has 5 vertices of even degree
Network 3 has 7 vertices of even degree
Network 4 has 9 vertices of even degree

Therefore, 3 of the 4 graphs can have an Euler Circuit.