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April 20, 2026, 08:32:16 pm

Author Topic: Conveyor belt+incline plane  (Read 1039 times)  Share 

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VCE_2012

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Conveyor belt+incline plane
« on: November 04, 2012, 10:06:43 pm »
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Consider a conveyor belt on an incline plane, an object mass  of m kg is placed at the bottom of the conveyor, the machine operates the conveyor belt so the object moves up the plane. I remember this from a past exam.
Correct me if I'm wrong by saying:
m*g*sin(theta)=Friction, when: Fnet is up or down the plane or zero.
where theta is the angle made with the ground and the plane.

abeybaby

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Re: Conveyor belt+incline plane
« Reply #1 on: November 04, 2012, 10:26:30 pm »
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thats correct assuming the block isnt accelerating

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Biceps

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Re: Conveyor belt+incline plane
« Reply #2 on: November 05, 2012, 12:02:52 am »
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Only if there is no acceleration up or down the plane.
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