My Solutions to Exam 1

[oneoneoneone]

I only wrote down my answers in order so I don't have the question numbers exactly:/

1. 3arctan(x/2) + 1/2 ln(x^2+4)
2. General solutions for cosx=0 and sinx =root(3)/2
3a. -1-I root3, 3
4a. 100g
b. 100g/(1+5root3)
5. A=-4
6. -4/13
7. 4/15
8. 4x/(1+x^2)^2
9a. (2t/root(t^2+2) -2t) i + (2t/root(t^2+2)=2) j
bi. 4root6/3
ii.
d. 7pi/12
10ai. [-2,2]
ii. R\[-1/5,1/5]
b. [-2,-1/5)u(1/5,2]
c. 5root7/16

[DJing]

Yep that's what I got! Although for 4a) I had 100g=980

meh same diff!

[horizon]

Why is it 100g?

[datfatcat]

Anyone got the paper? I can't remember my answers lol!!

[DJing]

Why is it 100g?

Resolving vertically with a net force of zero

T/2-50g = 0

so T=100g

[datfatcat]

If I remember right, 10 marks gone....f**K!

[rocket]

If I remember right, 10 marks gone....f**K!

Don't stress ! It definitely one of the harder VCAA exams ! I got ~28ish ! Your SS will still be awesome

[#1procrastinator]

I see some familiar numbers so not an epic fail then. A fail but not epic

[datfatcat]

I see some familiar numbers so not an epic fail then. A fail but not epic

LOL!

[WhoTookMyUsername]

fuck. included 1/5 and -1/5 fuck fuck fuck fuck fuck

35/40 GG

[Truck]

Not sure about 2 if you actually had to find cos(x) = 0 :/. Can anyone confirm?
EDIT: oops forgot which questions which
EDIT2:
ii. R\[-1/5,1/5]
- is wrong.

x is between (-inf, -1/5) U (1/5, inf)
iii) is also consequentially wrong, can't remember what it is exactly though

[WhoTookMyUsername]

yes you do have to find cos(x)=0

[DJing]

Not sure about 2 if you actually had to find cos(x) = 0 :/. Can anyone confirm?

also for the area question, it's 4/13 not -4/13, cause a) Area can't be negative and b) the graph was below the x-axis!

I'm sure it was a typo I doubt after all our methods 'training' we'd forget area was negative haha! And yes, you needed to find cos(x)=0, it was a sneaky VCAA trick...too bad they didn't succeed in fooling the spesh people!

EDIT: Actually -4/13 is right, 4/15 is the answer to the area question

[oneoneoneone]

-4/13 is the gradient question
Also the area was above the x-axis IIRC
y=(x-1)root(2-x)

I'm fairly certain ii is right though.

[Truck]

sucks with cos(x) = 0 ... lost a mark.

I'm confused, if you think -4/13 is the answer to the area question what is 4/15 the answer too? i forgot which questions which lol. And if you sketch the curve y=(x-1)root(2-x), the curve is below the x-axis