Hey guys 2012 Exam 2 , Question 2B about some stupid weather LOl here is the question
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Question B
The first thing you're told is that there are 8 wind speeds.
We know that Q1 = min (in this case) =2
We know that Q3 = max(in this case) = 4
So, you get:
2, __, __, __, __, __, __, 4.
Then, we're told the median is 3.5. Because we have 8 values, the position of the median will be the 4.5th. That is, the average of the 4th and 5th value should equal the median, which in this case is 3.5. So, if 3+4/2 = 3.5, we can fairy say that term 4= 3 and term 5=4.
So:
2, __, __, 3, 4, ___, __, 4.
Now, you know that your Q1 = 2.
So, your (2nd + 3rd term)/2 = 2.
Thus, 2+2/2 = 2. So terms 2 and 3 are 2.
So:
2, 2, 2, 3, 4, __, __, 4.
Now, Q3 is 4.
4+4/2 = 4. Hence, terms 6 and 7 are 4.
Your answer:
2, 2, 2, 3, 4, 4, 4, 4.
^ Hope this helped.
To check, I'd put those data entries into my calculator & construct a boxplot, from which I'd then check to see whether I was right or wrong.