Mathematics - a new basis

[ms.srki]

2.9 N comparability numbers "2.3"
Theorem - Two (more) numbers are comparable to
know who is higher (equal or smaller), which is the point of [.0] away
from the numerical point of 0th

EVIDENCE - Two numbers: 5> 3 (item number 5 [5] is far from the point
3 of [3] 5 is a number of third 4 = 4 (item number 4 [4] and the number of points
4 [4] are equidistant) 4 is equal to 4 .2 <6 (item number 6 [6] is
from the point of 2 [2] 2 less than sixth ). .(={>, =, <}.

The general form of a). .(b

Three numbers: a). .(b). .(c (general form, open, closed form (the
figure)).

w26.png

[size=150]...[/size]

[ms.srki]

2:10 Adding "2.2,2.3,2.4,2.5,2.7,2.8"
Theorem - Number (N, G_N, S.) and number (Nn, G_Nn, Sn) have
contact, item number (Nn, G_Nn, Sn) [0 ] ranges counts the number of
(N, G_N, S.) and connect.

EVIDENCE - 3 + [0 ] 3 = 3 or 3 + [.3 ] 3 = 3.
w27.png
3 + [1] 3 = 4 or 3 + [.2] 3 = 4
w28.png
3+[2]3=5 or 3+[1]3=5
w29.png
3+[3]3=6 or3+[.0]3=6 ili 3+3=6.
w30.png

The general form of a + [q] = c or b + a [. q] b = c
The general form of the opposite numbers
https://docs.google.com/file/d/0BzkWG0xdRpPYUTgtdXFTcERlTDA/edit?usp=sharing

This is the solution to start fasting
3+[0]3=3
3+[1]3=4
3+[2]3=5
3+[3]3=6

[alondouek]

This is the solution to start fasting

I look forward to using this theorem on Yom Kippur.

Cheers buddy!

[pi]

This is the solution to start fasting

[ms.srki]

2.11 comparability G_N number "2.10"
Theorem - Parts of gaps that are not /. a_n / are added
actions in addition [.0] and compared as natural numbers.

EVIDENCE - 4/.5/3 , 4+[.0]3=7 , a/.b/c , a+[.0]c=d .

6/.5./2/.4/3 , 6+[.0]2+[.0]3=11 , a/.b/c/.d/e , a+[.0]c+[.0]e=f .

3/.3/5/.2/7/.3/4 , 3+[.0]5+[.0]7+[.0]4=19 , a/.b/c/.d/e/.f/g ,
a+[.0]c+[.0]e+[.0]g=h .

...

[abcdqdxD]

can someone ban this guy?

[pi]

can someone ban this guy?

These insightful posts by ms.srki are the highlight of my day, so no ban

[Professor Polonsky]

[ms.srki]

2.12 Subtraction "2.10"
Theorem - The addition of a long relationship where the angle
delete this relationship, the rest remains.

Evidence - 3-[0]3=0 or 3-[.3]3=0 or3-3=0
w32.png
3-[1]3=1/.2/1 or 3-[.2]=1/.2/1
w33.png
3-[2]3=2/.1/2or 3-[.1]3=2/.1/2
w34.png
3-[3]3=6 or3-[.0]3=6
w35.png
The general form a-[q]b=c ili a-[.q]b=c

The general form  the opposite numbers
https://docs.google.com/file/d/0BzkWG0xdRpPYQlZjM2VzMmdRcGc/edit?usp=sharing

[MJRomeo81]

hahahaha wow dat translation!

[ms.srki]

TEST - see what you've learned
(2.8 - what part of the question)
1. 4/.3/2/.9/2s.=?
2. 50s.=?
3. 0/.22/5/.6/0=?
(2.10)
1. 5+[3]7=?
2. 6s.+[.2]1/.4/5/.3/0=?
3. 4/.5/3s.+[6]6/.2/3s.=?
(2.11)
1. 4/.6/3?1/.2/2/.2/1
2. 5/.2/2/.3/1?1/.6/2
3. 4/.3/2s.?6
(2.12)
1.6-[.2]7=?
2.1/.6/2-[3]6s.=?
3.7s.-[4]8s.=?
(2.13)
1.6-[3]8/.2/3s.=? ( - in square )
2.5/.2/3s.-[.2]6/.8/2/.4/2s.=?
3.3/.10/10/3-[.10]5/.6/3=?

[ShortBlackChick]

I havent learnt anything

[TrueTears]

TEST - see what you've learned
(2.8 - what part of the question)
1. 4/.3/2/.9/2s.=?

is the answer a mobile number?

[pi]

Love your work! I'll give these a go, although my understanding is somewhat rudimentary

TEST - see what you've learned
(2.8 - what part of the question)
1. 4/.3/2/.9/2s.=?
2. 50s.=?
3. 0/.22/5/.6/0=?

1. 4/.3/2/.9/2s. = {4/.3/2/.9/2, 0/.4/3/.2/9/.2}
2. 50s. = 0/.50/0 = {0/.5/0, 5}
3. 0/.22/5/.6/0 is unchanged due to no s?

(2.10)
1. 5+[3]7=?
2. 6s.+[.2]1/.4/5/.3/0=?
3. 4/.5/3s.+[6]6/.2/3s.=?

1. 5+[3]7 = 10
2. Got a bit lost, is this using info from 2.11?
3. Got a bit lost, is this using info from 2.11?

Got a bit lost with the whole of the 2.11 and 2.12 exercises, but I'm sure it wasn't your magnificent teaching style to blame.

I'm still absorbing your new and exciting concepts, so I can't answer the later questions

Thanks for this amazing insight!

Also, you haven't shown us 2.13 yet So we can't have a go at:

(2.13)
1.6-[3]8/.2/3s.=? ( - in square )
2.5/.2/3s.-[.2]6/.8/2/.4/2s.=?
3.3/.10/10/3-[.10]5/.6/3=?

[nacho]

my mobile number is 0430634746

awwwwww yiss!!