Login

Welcome, Guest. Please login or register.

May 12, 2026, 02:45:53 pm

Poll

UV-Visible and IR Spectroscopy are both referred to as absorption spectroscopy. This is because:

They both involve transitions to higher energy levels
they both involve electron transitions
they both require the use of visible light
they both measure radiation given out by a substance

Author Topic: Jacaranda Strikes again (or I'm just wrong)  (Read 620 times)  Share 

0 Members and 1 Guest are viewing this topic.

Chazef

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 249
  • Respect: +5
  • School: MLMC
Jacaranda Strikes again (or I'm just wrong)
« on: January 27, 2013, 12:03:10 am »
0
Hey I'm reluctantly doing the study-on guide for chem 3/4 by *shudders* jacaranda and this question really annoys me. I don't think any of these answers are good enough to explain why the two methods are referred to as 'absorption' spectroscopy as none of the answers really mention something being 'absorbed'. I'm thinking it can't be option 3 because IR-spectroscopy doesn't use visible light and it can't be option 2 because IR doesn't involve electron energy states. That leaves 1 and 4, both of which are true as far as I know. Because option 4 actually mentions radiation, which is something that can be absorbed, I chose that but it turns out the 'correct' answer is option 1. Was option 4 trying to refer to the substance being tested giving out radiation (rather than just radiation from a lamp)? Because from what I see, there's no good reason to favour option 1 over option 4. Could someone please enlighten me :) I feel like I'm overlooking something important. This feels like one of those times when somebody says 'they call it X for a reason' when the word itself gives no clues as to its meaning (in this case X is 'absorption')
2012: legal studies [41]
2013: physics [47], chemistry [45], englang [40], softdev [43], methods [44]
ATAR: 99.20
Computer Science @ Monash