Expressing a linear relationship as a function

[alondouek]

Having a major derp moment for STA1010...

I have a linear relationship . How do I express N as a function of t, i.e. as ?

[pi]

Are you sure that question is correct? :O

(not missing any logs etc.)

[domislong]

As far as I'm concerned it's already expressed as a function of t.

In the same way you could have f(x) = 10 + 5.5x, the convention is just y = f(x).

So for this case N = N(t), and it's a linear function.

[pi]

^Yeah exactly, which is why I suspect the question hasn't been copied done in its entirety haha

[alondouek]

Oh crap, missed the natural log 

should be:

[b^3]

N is already a function of t, although I remember this example from somewhere being after a transformation? Which in that case we would have to use our log laws, if we have base^power=answer, then 'log base of the answer gives the power'.

Which means your would be and your would be .

EDIT: oh good, I remembers the example from the lecture right.... (not sure if that's a good or bad thing here...)

[alondouek]

N is already a function of t, although I remember this example from somewhere being after a transformation? Which in that case we would have to use our log laws, if we have base^power=answer, then 'log base of the answer gives the power'.

Which means your would be and your would be .

EDIT: oh good, I remembers the example from the lecture right.... (not sure if that's a good or bad thing here...)

Thank you! Can't believe I've forgotten how to do this, my Methods teacher would kill me...