It mentions that the two genes are not independently assorted. This means that the two genes are actually linked.
SsWw x SsWw, if the two genes were unlinked, would result in offspring phenotypes in a 9:3:3:1 ratio. However, because the genes are linked, you're going to expect that there is a greater proportion of offspring with parental phenotypes relative to recombinant phenotypes. So, this means that to begin with, you're expecting to cross offspring with either of the parental phenotype (not recombinant), and so in fact, you're stemming it back to the parental phenotypes, long/straight and short/wavy, and so most offspring would show this phenotype than sat short/straight (which would be a recombinant phenotype). Hence, D is the answer.
I hope this helped.
I don't see how SsWw x SsWw is relevant here?
I mean 9:3:3:1 is exactly right but the question says it's a test cross. SsWw x ssww
If the genes were unlinked then you'd get equal 1:1:1:1 ratio
If the genes were linked and crossing over did not occur you'd get a 1:1 ratio
In this case, the genes were linked and crossing over occurred, therefore the parental genotypes would be greater in number than recombinant genotypes. you'd expect parental genotypes to be equal in number and recombinant genotypes to also be equal.
thus, D is the correct answer