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September 23, 2025, 07:43:43 am

Author Topic: MAX min problem!!  (Read 1676 times)  Share 

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naved_s9994

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MAX min problem!!
« on: July 05, 2009, 09:45:16 am »
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Mildred wants to construct a rectangular enclosure for her children to play in.

10 M rope

find max area
'Keep you friends close, but keep your enemies closer'

kj_

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Re: MAX min problem!!
« Reply #1 on: July 05, 2009, 10:43:49 am »
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Max area of any rectangular object = square.

Thus, each side of the square, and thus as max area.


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Of course, you can say , , find out that (because and thus , then diff A, let it equal 0, and get that y = 2.5 metres. :)
« Last Edit: July 05, 2009, 10:46:48 am by kj_ »

cobby

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Re: MAX min problem!!
« Reply #2 on: July 05, 2009, 10:47:26 am »
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Of course, you can say P = x + y, A = xy, find out that , then diff A, let it equal 0, and get that y = 2.5 metres. :)
Thats what i did :) :P








Sketch and find max
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naved_s9994

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Re: MAX min problem!!
« Reply #3 on: July 05, 2009, 11:07:15 am »
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yea guys i got same answer as you..lol thnx!

but i was wondering cant we let derivate = 0
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cobby

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Re: MAX min problem!!
« Reply #4 on: July 05, 2009, 11:40:03 am »
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yea guys i got same answer as you..lol thnx!

but i was wondering cant we let derivate = 0

yeh :)
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kj_

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Re: MAX min problem!!
« Reply #5 on: July 05, 2009, 12:03:35 pm »
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yea guys i got same answer as you..lol thnx!

but i was wondering cant we let derivate = 0


Yes, it's exactly what I did in my 2nd step, read it again :)

naved_s9994

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Re: MAX min problem!!
« Reply #6 on: July 08, 2009, 03:39:01 pm »
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ahh thnx kj_ !
'Keep you friends close, but keep your enemies closer'