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August 23, 2025, 02:27:39 am

Author Topic: Exam 1 Tentative Answers - Courtesy Itute  (Read 13688 times)  Share 

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fieldjus

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Exam 1 Tentative Answers - Courtesy Itute
« on: November 06, 2013, 11:34:22 am »
+1
Here are the solutions for exam 1, thanks to Itute

Q1a x+2xln(x)
Q1b 6e^9
Q2 1/ 8(4-2x)^4 or 1/ 128(x-2)^4 Thanks to Belmasta
Q3 g(x)=(3-cos2pix)/2pi
Q4 x=7pi/3, 11pi/3
Q5a x=18/25
Q5b x=-6
Q6 a=+/- 3/2
Q7a sum of prob =1
Q7bi E(X)=28/15
Q7bii Pr(X>=28/15)=8/15
Q8 2-4/pi
Q9a a=1-sqrt(2)
Q9b End points are (-2,8), (2,2), local max (1,3), sharp min point (1-sqrt(2),1)
Q9ci image h(x)=1/3 |x^2-2|
Q10a xe^(-x/5) sq units
Q10b x=5, max area of triangle=5/e sq units
Q10c Shaded area=2.5(5ln(2)-3) sq units

Q9cii domain of image [-3,1]

If you disagree with the answers, please reply with your own responses to these questions :)
« Last Edit: November 06, 2013, 11:37:39 am by fieldjus »
2012: Legal Studies
2013: English - Accounting - Further - Methods - Specialist

Sanguinne

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #1 on: November 06, 2013, 11:37:17 am »
+1
9b) where we required to show the local max and the sharp min point????

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Damoz.G

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #2 on: November 06, 2013, 11:39:50 am »
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No but I did as it helped with graphing the new function

BasicAcid, did your dream come true today? :P

fieldjus

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #3 on: November 06, 2013, 11:40:38 am »
0
9b) where we required to show the local max and the sharp min point????



No, only endpoints were required I believe.

Q9ci image h(x)=1/3 |x^2-2|
Wasn't that 1/3 (x-2)^2 with the mods?

I am pretty sure it is the answer they gave
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Edward21

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #4 on: November 06, 2013, 11:41:24 am »
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No but I did as it helped with graphing the new function
I use the points to help with the translation, but i didn't physically write them down because they said indicate the new endpoints.....IS IS ASSUMED WE HAVE TO INCLUDE THE OTHER STRANGE POINTS!?
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ikhalid

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #5 on: November 06, 2013, 11:42:59 am »
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How did u do 7 b and c

ikhalid

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #6 on: November 06, 2013, 11:43:38 am »
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How did u do q 10 c

a-rod

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #7 on: November 06, 2013, 11:44:27 am »
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Shit, are consequential marks a thing in methods?

Damoz.G

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #8 on: November 06, 2013, 11:45:11 am »
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Shit, are consequential marks a thing in methods?

Yes, there are consequential marks. Definitely! :)

Jayhowz

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #9 on: November 06, 2013, 11:46:22 am »
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ISN'T 10C (5e+(5/4))loge(4)-(30/4) or (10e+(5/2))loge(2)-(15/2)?

abcdqdxD

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #10 on: November 06, 2013, 11:50:16 am »
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will you lose a mark if you wrote E(X)=84/45 instead of 28/15?

fieldjus

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #11 on: November 06, 2013, 11:51:07 am »
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will you lose a mark if you wrote E(X)=84/45 instead of 28/15?

No that should be fine :)
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darklight

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #12 on: November 06, 2013, 11:53:00 am »
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Hey guys,

Do you think i'd lose a mark if I wrote + - (root 27 over 12) rather than + - 3/2.
Also if I didn't fully simply the area at the end?
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leflyi

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #13 on: November 06, 2013, 11:53:59 am »
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Yes probably..


And yes for the root(27) over 12 as well


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Damoz.G

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Re: Exam 1 Tentative Answers - Courtesy Itute
« Reply #14 on: November 06, 2013, 11:54:40 am »
0
Yes but it backfired up my ass and out of my mouth -_-

I can only imagine that happening. :P

Don't stress, Exam 2 is still not done - Time for lots of improvement. :D